The best and most correct answer among the choices provided by the question is the second choice , b. sodium hydroxide .
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i may be wrong but Use the normal boiling points: propane, C3H8, –42.1˚C; butane, C4H10, –0.5˚C; pentane, C5H12, 36.1˚C; hexane, C6H14, 68.7˚C; heptane, C7H16, 98.4˚C; to estimate the normal boiling point of octane, C8H18.
Answer:
16.5moles of CO2
Explanation:
Molar mass of O2 is 32g/Mol
No of mole = 880/32 = 27.5 moles
27.5 Mol of O2 gives X mole of CO2
5 mole of O2 gives 3 moles of CO2
No of mole of CO2 = (27.5×3)/ 5 = 16.5moles
Total of 127.013 C of charge is passed
Given
weight of Ag solution before current has passed = 1.7854 g
weight of Ag solution after current has passed = 1.8016 g
Molecular mass of Ag = 107.86 g
Faraday's Constant = 96485
First of all we have to apply Faraday's First Law of Electrolysis i.e
m = ZQ
where
Z is propotionality constant (g/C)
Q is charge (C)
Hence,
Z = Atomic mass of substance/ Faraday's Constant
= 
= 0.0011178 g/C
Now ,
change in mass before and after the passing of current (Δm)
Δm = 1.8016g-1.7854g
= 0.0162g
Now amount of coulombs passed = 
amount of coulombs passed = 127.03524 C
Thus from the above conclusion we can say that amount of coulombs have passed is 127.03524 C
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<span>C. 5 protons, 5 electrons, and 6 neutrons</span>