They are all rocks and they are all solid
Answer:
The correct answer is: K'= 0.033.
Explanation:
The formation of HI from H₂ and I₂ is given by:
H₂ + I₂ → 2 HI K= 29.9
The decomposition of HI is the reverse reaction of the formation of HI:
2 HI → H₂ + I₂ K'
Thus, K' is the equilibrium constant for the reverse reaction of formation of HI. It is calculated as the reciprocal of the equilibrium constant of the forward reaction (K):
K' = 1/K = 1/(29.9)= 0.033
Therefore, the equilibrium constant for the decomposition of HI is K'= 0.033
Answer : The amount left of leutium-176 will be, 2.10 g
Solution :
First we have to calculate the rate constant, we use the formula :
![k=\frac{0.693}{t_{1/2}}](https://tex.z-dn.net/?f=k%3D%5Cfrac%7B0.693%7D%7Bt_%7B1%2F2%7D%7D)
Now we have to calculate the amount left of the sample.
Expression for rate law for first order kinetics is given by :
where,
k = rate constant =
t = decay time =
a = initial amount of the sample = 16.8 g
a - x = amount left after decay process = ?
Now put all the given values in above equation, we get
Therefore, the amount left of leutium-176 will be, 2.10 g