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ladessa [460]
3 years ago
15

Every day, each person in Canada throws out about 2.2 kg of garbage. If the population of Canada is 31 900 000, the total mass o

f garbage that all Canadians throw out each day is
Chemistry
1 answer:
krok68 [10]3 years ago
8 0

Answer:

70 180 000 kg

Explanation:

We can solve this problem by multiplying the amount of garbage each Canadian throws out each day (2.2 kg) by the number of Canadians:

  • 2.2 kg/person * 31 900 000 persons = 70 180 000

Thus according to this problem, all Canadians throw out 70 180 000 kg of garbage each day.

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A student decides to conduct an investigation to determine the boiling points of water and ethanol. The student will heat sample
lilavasa [31]
Deciding on the appropriate equipment
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2 years ago
3.
belka [17]

Answer:

3. Inverse 1. Direct

Explanation:

P- pressure

V - volume

T - temperature

P1*V1 / T1 = P2*V2 / T2 ...... (1)

That's the general gas law with the combined ideas of charles, boyle & lussac.

Whenever you are restricted as "constant" temperature, volume, or pressure...cancel them off of your equation.

in this case 3. is indirectly telling us to cancel the temperature (T).

so we'll be left w P1*V1 = P2*V2

now notice that any relation ship that is multiplied like the one above consists of inversely related quantities. & so we conclude that-

P & V are inversely proportional or have an inverse relationship.

similarly in 1. we'll cancel p off of the general formula (1)

to be left with V1/T1 = V2/T2

also note that quantities involved in division are directly related to each other & hence the answer.

5 0
2 years ago
__Ca(OH)2 + __ (NH4)2SO4 ----- &gt; ___CaSO4 + ___NH3 + __H2O<br><br> A)11<br> B)5<br> C)7<br> D)9
katovenus [111]
There would be a 2 infront of the NH3 and and 2 Infront of the H2O
6 0
3 years ago
Pcl5 exist but ncl5 does not.why?
jeyben [28]
N is as electronegative as Cl is. So Cl doesnt react with O, N
6 0
2 years ago
The Haber Process synthesizes ammonia at elevated temperatures and pressures. Suppose you combine 1580 L of nitrogen gas and 351
ikadub [295]

Answer : The volume of reactant measured at STP left over is 409.9 L

Explanation :

First we have to calculate the moles of N_2 and H_2 by using ideal gas equation.

<u>For N_2 :</u>

PV_{N_2}=n_{N_2}RT

where,

P = Pressure of gas at STP = 1 atm

V = Volume of N_2 gas = 1580 L

n = number of moles N_2 = ?

R = Gas constant = 0.0821L.atm/mol.K

T = Temperature of gas at STP = 273 K

Putting values in above equation, we get:

1atm\times 1580L=n_{N_2}\times (0.0821L.atm/mol.K)\times 273K

n_{N_2}=70.49mole

<u>For H_2 :</u>

PV_{H_2}=n_{H_2}RT

where,

P = Pressure of gas at STP = 1 atm

V = Volume of H_2 gas = 3510 L

n = number of moles H_2 = ?

R = Gas constant = 0.0821L.atm/mol.K

T = Temperature of gas at STP = 273 K

Putting values in above equation, we get:

1atm\times 3510L=n_{H_2}\times (0.0821L.atm/mol.K)\times 273K

n_{H_2}=156.6mole

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

N_2(g)+3H_2(g)\rightarrow 2NH_3(g)

From the balanced reaction we conclude that

As, 3 mole of H_2 react with 1 mole of N_2

So, 156.6 moles of H_2 react with \frac{156.6}{3}\times 1=52.2 moles of N_2

From this we conclude that, N_2 is an excess reagent because the given moles are greater than the required moles and H_2 is a limiting reagent and it limits the formation of product.

Now we have to calculate the excess moles of N_2 reactant (unreacted gas).

Excess moles of N_2 reactant = 70.49 - 52.2 = 18.29 moles

Now we have to calculate the volume of reactant, measured at STP, is left over.

PV=nRT

where,

P = Pressure of gas at STP = 1 atm

V = Volume of gas = ?

n = number of moles of unreacted gas = 18.29 moles

R = Gas constant = 0.0821L.atm/mol.K

T = Temperature of gas at STP = 273 K

Putting values in above equation, we get:

1atm\times V=18.29mole\times (0.0821L.atm/mol.K)\times 273K

V=409.9L

Therefore, the volume of reactant measured at STP left over is 409.9 L

8 0
3 years ago
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