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Fantom [35]
3 years ago
11

Decide whether a chemical reaction happens in either of the following situations. If a reaction does happen, write the chemical

equation for it. Be sure your chemical equation is balanced and has physical state symbols. situation chemical reaction.
A strip of solid magnesium metal is put into a beaker of 0.042M SnCl3 solution.
Chemistry
1 answer:
romanna [79]3 years ago
6 0

Answer: 3Mg(s)+2SnCl_3(aq)\rightarrow 3MgCl_2(aq)+2Sn(s)

Explanation:

Single replacement reaction is a chemical reaction in which more reactive element displaces the less reactive element from its salt solution.

A more reactive element is one which can easily lose or gain electrons as compared to the other element.

As Magnesium is more reactive than tin, it can easily displace tin from its salt solution (SnCl_3) and form magnesium chloride and tin in elemental form.

The balanced chemical equation is:

3Mg(s)+2SnCl_3(aq)\rightarrow 3MgCl_2(aq)+2Sn(s)

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A strand of messenger RNA coding the synthesis of a protein with 146 amino acids must have a string of___________ bases along it
svetlana [45]

Answer:

Since the relationship between amino acid and codon bases would be the values of 3 nitrogenous bases per 1 amino acid.

knowing this relationship what you would do is simply multiply 146 x 3 to find the number of codon bases which would be C. 438.

8 0
3 years ago
The graph below shows how the temperature and volume of a gas vary when the number of moles and the pressure of the gas are held
DedPeter [7]

Answer:

Option C. By increasing the temperature

Explanation:

From the graphical illustration above, we see clearly that the volume and temperature of the gas are directly proportional. This implies that as the temperature increases, the volume will also increase and as the temperature decreases, the volume will also decrease. This can further be explained by using the ideal gas equation as shown below:

PV = nRT

P is the pressure.

V is the volume.

n is the number of mole.

R is the gas constant.

T is the temperature.

PV = nRT

Divide both side by P

V = nRT/P

Since n and P are constant, the equation above becomes:

V & T

V = KT

K is the constant.

The above equation i.e V = KT implies that:

As T increases, V will also increase and as T decreases, V will also decrease.

Considering the question given above,

The volume of the gas can be increased if the temperature is increased.

6 0
4 years ago
What is formed when two or more atoms join together chemically
Mariana [72]

A molecule is formed

7 0
3 years ago
What happens to atomic radius size of a cation and why?
slamgirl [31]
A cation is a positive ion. That means it lost an electron.
7 0
3 years ago
Help asap <br> help show work <br> I need an A
MrRissso [65]

Answer:   17 (a) 360,000 ms         18 (a) 0.245 s

                     (b) 4.800 kg                   (b) 500 cm

                     (c) 560.0 dm                  (c) 68.00 m

                     (d) 72,000 mg                (d) 0.025 Mg

<u>Explanation:</u>

Use the following table.  Note the direction you are going to:

Right means move decimal to the right. Left means move decimal to the left.

               \boxed{\begin{array}{c|c|c|c|c|c|c|c|c|c}Mega&x&x&kilo&x&deka&unit&deci&centi&milli\\M\_\_&&&k\_\_&&dk\_\_&\_\_\_&d\_\_\)&c\_\_&m\_\_\end{array}}

**********************************************************************************************

17(a) 360 s to ms                                                        o       →         →        →o

                            \boxed{\begin{array}{c|c|c|c|c|c|c|c|c|c}Mega&x&x&kilo&x&deka&unit&deci&centi&milli\\M\_\_&&&k\_\_&&dk\_\_&\_\_\_&d\_\_\)&c\_\_&m\_\_\end{array}}

Move the decimal 3 places to the right   -->   360_ _ _.

Fill in the blanks with zeroes   --> 360,000

  (b) 4800 g to kg                            o←    ←     ←         o

                             \boxed{\begin{array}{c|c|c|c|c|c|c|c|c|c}Mega&x&x&kilo&x&deka&unit&deci&centi&milli\\M\_\_&&&k\_\_&&dk\_\_&\_\_\_&d\_\_\)&c\_\_&m\_\_\end{array}}

Move the decimal 3 places to the left   --> 4.<u>8</u> <u>0</u> <u>0</u>

<u />

 (c) 5600 dm to m                                                       o←     o

                             \boxed{\begin{array}{c|c|c|c|c|c|c|c|c|c}Mega&x&x&kilo&x&deka&unit&deci&centi&milli\\M\_\_&&&k\_\_&&dk\_\_&\_\_\_&d\_\_\)&c\_\_&m\_\_\end{array}}

Move the decimal 1 place to the left   --> 560. <u>0</u>

<u />

 (d)  72 g to mg                                                         o         →        →        →o

                            \boxed{\begin{array}{c|c|c|c|c|c|c|c|c|c}Mega&x&x&kilo&x&deka&unit&deci&centi&milli\\M\_\_&&&k\_\_&&dk\_\_&\_\_\_&d\_\_\)&c\_\_&m\_\_\end{array}}

Move the decimal 3 places to the right   --> 72 _ _ _.

Fill in the blanks with zeroes   -->     72,000

***********************************************************************************************

18 (a) 245 ms to s                                                       o←       ←       ←        o

                             \boxed{\begin{array}{c|c|c|c|c|c|c|c|c|c}Mega&x&x&kilo&x&deka&unit&deci&centi&milli\\M\_\_&&&k\_\_&&dk\_\_&\_\_\_&d\_\_\)&c\_\_&m\_\_\end{array}}

Move the decimal 3 places to the left -->   . <u>2</u> <u>4</u> <u>5</u>

     (b) 5 m to cm                                                        o        →        →o

                             \boxed{\begin{array}{c|c|c|c|c|c|c|c|c|c}Mega&x&x&kilo&x&deka&unit&deci&centi&milli\\M\_\_&&&k\_\_&&dk\_\_&\_\_\_&d\_\_\)&c\_\_&m\_\_\end{array}}

Move the decimal 2 places to the right   -->   5 _ _.

Fill in the blanks with zeroes   -->    500

      (c) 6800 cm to m                                                 o←      ←        o

                             \boxed{\begin{array}{c|c|c|c|c|c|c|c|c|c}Mega&x&x&kilo&x&deka&unit&deci&centi&milli\\M\_\_&&&k\_\_&&dk\_\_&\_\_\_&d\_\_\)&c\_\_&m\_\_\end{array}}

Move the decimal 2 places to the left   -->   68. <u>0</u> <u>0 </u>

<u />

    (d)  25 kg to Mg    o←    ←    ←    o

                            \boxed{\begin{array}{c|c|c|c|c|c|c|c|c|c}Mega&x&x&kilo&x&deka&unit&deci&centi&milli\\M\_\_&&&k\_\_&&dk\_\_&\_\_\_&d\_\_\)&c\_\_&m\_\_\end{array}}

Move the decimal 3 places to the left -->   . _ 25

Fill in the blanks with zeroes  -->   .025

6 0
4 years ago
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