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Alja [10]
3 years ago
13

Help asapppppppppp plsssssssssssss

Chemistry
2 answers:
trapecia [35]3 years ago
7 0
One there is one atom
tia_tia [17]3 years ago
5 0
There is one N atom
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The motion becomes smaller. Lets tale the example of water. At gaseous state, the particles moves rapidly in all directions. As it is cooled, it becomes liquid and the motion becomes smaller because the particles are now closer to each other as the attraction forces becomes stronger. As it is cooled further, it becomes solid. At solid state, the particles now vibrate in fixed position. Apply this concept to motion of molecules in a substance.
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If you are trying to measure an
Tamiku [17]

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4 years ago
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The area that deals with the mechanism, the rate, and the energy transfer that occurs when matter undergoes a change
mafiozo [28]
Physical chemistry is the area that deals with the mechanisms, the rate, and the energy transfer that occurs when matter undergoes a change. So the correct option for the given question is option “B”. Whenever there is a change in the state of matter, the physical properties definitely undergo a change. A solid matter will always have a definite shape and volume, while a liquid has a definite volume but no shape. Gases do not have either definite volume or shape. Chemical properties might not be affected, but physical properties are definitely impacted when a matter undergoes change.



7 0
3 years ago
HELP NOW!!
s2008m [1.1K]

Given, mass of isotope 1 = 39.06 amu

% abundance of isotope 1 = 10.00%

mass of isotope 2 =  42.14 amu

% abundance of isotope 2 = 90.00%

Average atomic mass

= [ (mass of isotope 1  x % abundance of isotope 1 ) + (mass of isotope 2 x % abundance of isotope 2 ) ]/ 100

= [(39.06 x 10) + (42.14 x 90)]/100

= (390.6 + 3792.6) / 100

= 4183.2/100

= 41.8 (to the nearest tenth)

Therefore, the weighted atomic mass of element Q is 41.8 amu.

6 0
3 years ago
The equilibrium constant kp for the thermal decomposition of no2 is 6.5 × 10–6 at 450°c. if a reaction vessel at this temperatur
Fed [463]
We let x be the pressure of each product at equilibrium, giving this ICE table:
                                           2NO2 (g) ↔ 2NO (g) + O2 (g)
     Initial pressure (atm):    0.500            0               0
     Change (atm):               -2x                +2x           +x
     Equilibrium (atm):          0.500-2x       2x             x

We can calculate x from Kp:
     Kp = [NO]^2 [O2] / [NO2]^26.5x10^-6 = (2x)^2 (x) / (0.500-2x)^2

Approximating that 2x is negligible compared to 0.500 simplifies the equation to 
     6.5x10^-6 = (2x)^2 (x)/(0.500)^2 = 4x^3 / (0.500)^2

Then we solve for x:
     x3 = (6.5x10^-6)(0.500)^2 / 4
     x = 0.00741

The pressure of NO2 at equilibrium is therefore 
     Pressure of NO2 = 0.500-2x = 0.500 - 2(0.00741) = 0.4852 atm
3 0
3 years ago
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