The motion becomes smaller. Lets tale the example of water. At gaseous state, the particles moves rapidly in all directions. As it is cooled, it becomes liquid and the motion becomes smaller because the particles are now closer to each other as the attraction forces becomes stronger. As it is cooled further, it becomes solid. At solid state, the particles now vibrate in fixed position. Apply this concept to motion of molecules in a substance.
Answer:
Usually you have V, for voltage, Ohms for resistance, and Coulombs for charge.
Explanation:
See the image attached :)
Physical chemistry is the area that deals with the
mechanisms, the rate, and the energy transfer that occurs when matter undergoes
a change. So the correct option for the given question is option “B”. Whenever
there is a change in the state of matter, the physical properties definitely
undergo a change. A solid matter will always have a definite shape and volume,
while a liquid has a definite volume but no shape. Gases do not have either definite
volume or shape. Chemical properties might not be affected, but physical
properties are definitely impacted when a matter undergoes change.
Given, mass of isotope 1 = 39.06 amu
% abundance of isotope 1 = 10.00%
mass of isotope 2 = 42.14 amu
% abundance of isotope 2 = 90.00%
Average atomic mass
= [ (mass of isotope 1 x % abundance of isotope 1 ) + (mass of isotope 2 x % abundance of isotope 2 ) ]/ 100
= [(39.06 x 10) + (42.14 x 90)]/100
= (390.6 + 3792.6) / 100
= 4183.2/100
= 41.8 (to the nearest tenth)
Therefore, the weighted atomic mass of element Q is 41.8 amu.
We let x be the pressure of each product at equilibrium, giving this ICE table:
2NO2 (g) ↔ 2NO (g) + O2 (g)
Initial pressure (atm): 0.500 0 0
Change (atm): -2x +2x +x
Equilibrium (atm): 0.500-2x 2x x
We can calculate x from Kp:
Kp = [NO]^2 [O2] / [NO2]^26.5x10^-6 = (2x)^2 (x) / (0.500-2x)^2
Approximating that 2x is negligible compared to 0.500 simplifies the equation to
6.5x10^-6 = (2x)^2 (x)/(0.500)^2 = 4x^3 / (0.500)^2
Then we solve for x:
x3 = (6.5x10^-6)(0.500)^2 / 4
x = 0.00741
The pressure of NO2 at equilibrium is therefore
Pressure of NO2 = 0.500-2x = 0.500 - 2(0.00741) = 0.4852 atm
