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Serjik [45]
3 years ago
5

A wave has an amplitude of 0.2 cm.

Physics
1 answer:
Anettt [7]3 years ago
3 0
The distance between the resting point and maximum height of the wave is 0.2 cm.

The amplitude is measured from the resting point up to the highest point of the wave.
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3 years ago
I need help answering a, b , and c. please.​
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Answer:

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6 0
3 years ago
A proton is shot perpendicularly at an infinite plane of charge. The charge density of the plane is +7.65×10^−4 C/m^2. If the pr
Alexeev081 [22]

Answer:

The velocity is 2.94\times10^{6}\ m/s.

Explanation:

Given that,

Charge density of the plane \sigma=7.65\times10^{−4}\ C/m^2

Distance = 1.05 mm

We need to calculate the electric field due to plane of charge

Using formula of electric field

E=\dfrac{\sigma}{2\epsilon}

Put the value into the formula

E=\dfrac{7.65\times10^{−4}}{2\times8.85\times10^{-12}}

E=4.322\times10^{7}\ N/C

We need to calculate potential difference

Using formula of potential difference

V=E\times r

Put the value into the formula

V=4.322\times10^{7}\times1.05\times10^{-3}

V=4.5381\times10^{4}\ Volt

We need to calculate the work requires to be done to reach the surface of the plane

Using formula of work done

W=qV

Put the value into the formula

W = 1.6\times10^{-19}\times4.5381\times10^{4}

W=7.26096\times10^{-15}\ J

We need to calculate the velocity

Using work energy theorem

W=\dfrac{1}{2}mv^2

v^2=\dfrac{2W}{m}

v=\sqrt{\dfrac{2\times7.26096\times10^{-15}}{1.67\times10^{-27}}}

v=2.94\times10^{6}\ m/s

Hence, The velocity is 2.94\times10^{6}\ m/s.

8 0
3 years ago
A ball is thrown vertically upward and then comes back down. During the ball's flight up and down, its velocity and acceleration
Dovator [93]

During the ball's flight up its velocity and acceleration vectors are in opposite direction and during the ball's flight down its velocity and acceleration vectors are in same direction.

  • The velocity vector is always in the direction of motion of the object. So, during the ball's flight up its velocity vector is in the upward direction (90°) and during the ball's flight down its velocity vector is in the downward direction (270°).
  • When there is a positive acceleration in the object the acceleration vector is in the direction of motion of the object. When there is a negative acceleration in the object the acceleration vector is in the opposite direction of motion of the object. So, during the ball's flight up its acceleration vector is in the downward direction (270°) and during the ball's flight down its acceleration vector is in the upward direction (90°).

Velocity vector is the rate of change of position of an object. Acceleration vector is the rate of change of velocity of an object.

Therefore, during the ball's flight up its velocity and acceleration vectors are in opposite direction and during the ball's flight down its velocity and acceleration vectors are in same direction.

To know more about velocity and acceleration vectors

brainly.com/question/13492374

#SPJ4

6 0
1 year ago
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