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2 years ago

What average force is required to stop a 980 kg car in 9.0 s if the car is traveling at 91 km/h ?

1 answer:

5 0

Newton's second law of motion:
F=ma
$a = \frac{v}{t}$
You convert from km/h to m/s by dividing by 3.6:
$v = 91 \div 3.6$
$v = 25.3 \: \frac{m}{s}$
Then a is:
$a = \frac{25.3}{9}$
$a = 2.8 \frac{m}{s {}^{2} }$
Then:
F=(980)(2.8)=2744 N

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Which of the following biomes might be found at a latitude of 33° South?

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2 years ago

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oksano4ka [1.4K]

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3 years ago

Read 2 more answers

a uniform rule balance on a knife edge at the 55cm mark when a mass of 40g is hung from the 95cm mark. find the weight of the ru

BigorU [14]

Answer:

W = 3.1 N

Explanation:

moments about any convenient point will sum to zero.

I choose summing about the knife edge mark and will assume the ruler of weight W is of uniform construction.

I will assume the ruler weight makes a positive moment

W[55 - 50) - 0.040(9.8)[ 95 - 55] = 0

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2 years ago

What is an example of a invertebrate that doesn’t have an exoskeleton?

Tatiana [17]

Invertebrate means those organism which doesnot have backbone in their body .Some of the examples are:

1.Spider

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3.Starfish

4.Sea urchins.

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3 years ago

Read 2 more answers

An archer defending a castle is on an 15.5 m high wall. He shoots an arrow straight down at 22.8 m/s. How much time does it take

kodGreya [7K]

Answer:

about 602 milliseconds

Explanation:

The motion can be approximated by the equation ...

y = -4.9t^2 -22.8t +15.5

where t is the time since the arrow was released, and y is the distance above the ground.

When y=0, the arrow has hit the ground.

Using the quadratic formula, we find ...

t = (-(-22.8) ± √((-22.8)^2 -4(-4.9)(15.5)))/(2(-4.9))

= (22.8 ± √823.64)/(-9.8)

The positive solution is ...

t ≈ 0.60195193

It takes about 602 milliseconds for the arrow to reach the ground.

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3 years ago