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3 years ago

A first aid provider is trained to do the following except:

Physics

1 answer:

Elodia [21]3 years ago

7 0

A.
They’re supposed to help the person and cannot diagnose them as that is the job of a doctor

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A metal sample of mass M requires a power input P to just remain molten. When the heater is turned off, the metal solidifies in

vovangra [49]

Answer:

L = Pt/M

Explanation:

Power, P= Q/t = mL/t

we know that, (Q=m×l)

Now ⇒l= Pt/M

Thus l= Pt/M

4 0

3 years ago

A long, thin solenoid has 450 turns per meter and a radius of 1.17 cm. The current in the solenoid is increasing at a uniform ra

sergey [27]

Answer:

$\frac{di}{dt} = 7.31 \ A/s$

Explanation:

From the question we are told that

The number of turns is $N = 450 \ turns$

The radius is $r = 1.17 \ cm = 0.0117 \ m$

The position from the center consider is x = 3.45 cm = 0.0345 m

The induced emf is $e = 8.20 *10^{-6} \ V/m$

Generally according to Gauss law

$\int\limits { e } \, dl = \mu_o * N * \frac{di}{dt } * A$

=> $e * 2\pi x = \mu_o * N * \frac{d i }{dt } * A$

Where A is the cross-sectional area of the solenoid which is mathematically represented as

$A = \pi r ^2$

=> $e * 2\pi x = \mu_o * N * \frac{d i }{dt } * \pi r^2$

=> $\frac{di}{dt} = \frac{2e * x }{\mu_o * N * r^2}$ ggl;

Here $\mu_o$ is the permeability of free space with value

$\mu_o = 4\pi * 10^{-7} \ N/A^2$

=> $\frac{di}{dt} = \frac{2 * 8.20*10^{-6} * 0.0345 }{ 4\pi * 10^{-7} * 450 * (0.0117)^2}$

=> $\frac{di}{dt} = 7.31 \ A/s$

6 0

4 years ago

A hollow plastic sphere is held below the surface of a fresh-water lake by a cord anchored to the bottom of the lake. The sphere

Naya [18.7K]

Answer: a) B = 6811N

b) m = 603.2kg

c) 86.8%

Explanation: Buoyant force is a force a fluid exerts on a submerged object.

It can be calculated as:

$B=\rho_{fluid}.V_{obj}.g$

where:

$\rho_{fluid}$ is density of the fluid the object is in;

$V_{obj}$ is volume of the object;

g is acceleration due to gravity, is constant and equals 9.8m/s²

a) For the hollow plastic sphere, density of water is 1000kg/m³:

$B=10^{3}.0.695.9.8$

B = 6811N

b) Anchored to the bottom, the forces acting on the sphere are Buoyant, Tension and Force due to gravity:

B = T + $F_{g}$

B = T + mg

mg = B - T

$m=\frac{B - T}{g}$

Calculating:

$m=\frac{6811 - 900}{9.8}$

m = 603.2kg

c) When the shpere comes to rest on the surface of the water, there are only buoyant and gravity acting on it:

B = m.g

$\rho_{w}.V_{sub}.g=m.g$

$V_{sub}=\frac{m}{\rho_{w}}$

$V_{sub}=\frac{603.2}{1000}$

$V_{sub}$ = 0.6032m³

Fraction of the submerged volume is:

$\frac{V_{sub}}{V_{obj}}$ = $\frac{0.6932}{0.695}$ = 0.868

3 0

3 years ago

A birdcage with mass 22.5kg at rest on a living room floor is acted on by a net horizontal force of

patriot [66]

m = mass of the birdcage = 22.5 kg

F = net force acting on birdcage to move it = 140 N

a = acceleration produced due to the force applied

Using newton's second law

a = F/m

inserting the values

a = 140/22.5

a = 6.22 m/s²

t = time of travel of crate = 10.5 s

v₀ = initial velocity of the crate = 0 m/s

X = displacement of the crate

displacement of the crate is given as

X = v₀ t + (0.5) a t²

X = 0 (10.5) + (0.5) (6.22) (10.5)²

X = 342.88 m

7 0

3 years ago

Read 2 more answers

Q.1- A 3000 cm3 tank contain O2 gas at 20 °C and a gauge pressure of 2.5 x 106 Pa. Find the mass of oxygen in the tank.

exis [7]

20c because te mass of the object is larger than the table

3 0

3 years ago