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sergey [27]
3 years ago
6

A first aid provider is trained to do the following except:

Physics
1 answer:
Elodia [21]3 years ago
7 0
A.
They’re supposed to help the person and cannot diagnose them as that is the job of a doctor
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A metal sample of mass M requires a power input P to just remain molten. When the heater is turned off, the metal solidifies in
vovangra [49]

Answer:

L = Pt/M

Explanation:

Power, P= Q/t = mL/t

​

we know that, (Q=m×l)

Now ⇒l= Pt/M

​

Thus l= Pt/M

​

4 0
3 years ago
A long, thin solenoid has 450 turns per meter and a radius of 1.17 cm. The current in the solenoid is increasing at a uniform ra
sergey [27]

Answer:

\frac{di}{dt}  = 7.31 \  A/s

Explanation:

From the question we are told that  

     The  number of turns is  N =  450 \  turns

      The  radius is  r =  1.17 \ cm =  0.0117 \ m

       The  position from the center consider is  x =  3.45 cm  =  0.0345 m

       The  induced emf is  e  =  8.20 *10^{-6} \  V/m

Generally according to Gauss law

        \int\limits { e } \, dl  =  \mu_o *  N  *  \frac{di}{dt }  *  A

=>    e *  2\pi x  =  \mu_o  *  N  *  \frac{d i }{dt }  *  A

Where A is the  cross-sectional area of the solenoid which is mathematically represented as

                A =  \pi r ^2

=>      e *  2\pi x  =  \mu_o  *  N  *  \frac{d i }{dt }  *  \pi r^2

=>       \frac{di}{dt}  =  \frac{2e * x  }{\mu_o * N  * r^2}ggl;

Here  \mu_o is the permeability of free space with value

          \mu_o  =  4\pi * 10^{-7} \  N/A^2

=>     \frac{di}{dt}  =  \frac{2 *  8.20*10^{-6} *  0.0345  }{ 4\pi * 10^{-7} * 450  * (0.0117)^2}

=>      \frac{di}{dt}  = 7.31 \  A/s

6 0
4 years ago
A hollow plastic sphere is held below the surface of a fresh-water lake by a cord anchored to the bottom of the lake. The sphere
Naya [18.7K]

Answer: a) B = 6811N

              b) m = 603.2kg

              c) 86.8%

Explanation: <em>Buoyant force</em> is a force a fluid exerts on a submerged object.

It can be calculated as:

B=\rho_{fluid}.V_{obj}.g

where:

\rho_{fluid} is density of the fluid the object is in;

V_{obj} is volume of the object;

g is acceleration due to gravity, is constant and equals 9.8m/s²

a) For the hollow plastic sphere, density of water is 1000kg/m³:

B=10^{3}.0.695.9.8

B = 6811N

b) Anchored to the bottom, the forces acting on the sphere are <u>Buoyant</u>, <u>Tension</u> and <u>Force due to gravity</u>:

B = T + F_{g}

B = T + mg

mg = B - T

m=\frac{B - T}{g}

Calculating:

m=\frac{6811 - 900}{9.8}

m = 603.2kg

c) When the shpere comes to rest on the surface of the water, there are only <u>buoyant</u> <u>and</u> <u>gravity</u> acting on it:

B = m.g

\rho_{w}.V_{sub}.g=m.g

V_{sub}=\frac{m}{\rho_{w}}

V_{sub}=\frac{603.2}{1000}

V_{sub} = 0.6032m³

Fraction of the submerged volume is:

\frac{V_{sub}}{V_{obj}} = \frac{0.6932}{0.695} = 0.868

<u />

3 0
3 years ago
A birdcage with mass 22.5kg at rest on a living room floor is acted on by a net horizontal force of
patriot [66]

m = mass of the birdcage = 22.5 kg

F = net force acting on birdcage to move it = 140 N

a = acceleration produced due to the force applied

a)

Using newton's second law

a = F/m

inserting the values

a = 140/22.5

a = 6.22 m/s²


b)

t = time of travel of crate = 10.5 s

v₀ = initial velocity of the crate = 0 m/s

X = displacement of the crate

displacement of the crate is given as

X = v₀ t + (0.5) a t²

X = 0 (10.5) + (0.5) (6.22) (10.5)²

X = 342.88 m

7 0
3 years ago
Read 2 more answers
Q.1- A 3000 cm3 tank contain O2 gas at 20 °C and a gauge pressure of 2.5 x 106 Pa. Find the mass of oxygen in the tank.
exis [7]
20c because te mass of the object is larger than the table
3 0
3 years ago
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