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2 years ago

Write down the boiling point and freezing point of mercury an alcohol

Physics

1 answer:

nekit [7.7K]2 years ago

8 0

Mercury has a high boiling point of 357 degrees C.
Mercury has a freezing point of −39 degrees C.

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Jack tries to place magnets on the door of his refrigerator. He observes that the magnets don’t stick. He guesses that the door

zaharov [31]

The answer is D.) Make observations

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2 years ago

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if a train starts from rest and attains a velocity of 100m/s in 25 seconds. calculate the acceleration produced by the train.

stira [4]

-4 km/s2

Explanation:
0-100/25
-100/25
-4

5 0

2 years ago

Consider the interference pattern produced by two parallel slits of width a and separation d, in which d = 3a. The slits are ill

laila [671]

Answer:

a) m =1 θ = sin⁻¹ λ / d, m = 2 θ = sin⁻¹ ( λ / 2d) , c) m = 3

Explanation:

a) In the interference phenomenon the maxima are given by the expression

d sin θ = m λ

the maximum for m = 1 is at the angle

θ = sin⁻¹ λ / d

the second maximum m = 2

θ = sin⁻¹ ( λ / 2d)

the third maximum m = 3

θ = sin⁻¹ ( λ / 3d)

the fourth maximum m = 4

θ = sin⁻¹ ( λ / 4d)

b) If we take into account the effect of diffraction, the intensity of the maximums is modulated by the envelope of the diffraction of each slit.

I = I₀ cos² (Ф) (sin x / x)²

Ф = π d sin θ /λ

x = pi a sin θ /λ

where a is the width of the slits

with the values of part a are introduced in the expression and we can calculate intensity of each maximum

c) The interference phenomenon gives us maximums of equal intensity and is modulated by the diffraction phenomenon that presents a minimum, when the interference reaches this minimum and is no longer present

maximum interference d sin θ = m λ

first diffraction minimum a sin θ = λ

we divide the two expressions

d / a = m

In our case

3a / a = m

m = 3

order three is no longer visible

7 0

2 years ago

Projectile Motion: A hobbyist launches a projectile from ground level on a horizontal plain. It reaches a maximum height of 72.3

marin [14]

Answer:

The angle of launch from the horizontal direction is 20.99° .

Explanation:

Let u and θ be the initial speed and angle of projection from the horizontal axis of the object respectively.

The equations for projectile motion are :

H = ( u² sin²θ)/ 2g ......(1)

Here H is maximum height of the projectile motion and g is acceleration due to gravity.

R = ( u² sin2θ)/g .......(2)

Here R is the maximum horizontal displacement of the object.

Rearrange equation (1) in terms of u².

u² = (2gH)/sin²θ

Substitute this equation in equation (2).

R = (2gH sin2θ) / (sin²θ x g)

R = (2H sin2θ)/sin²θ

Using trigonometry property, sin2θ = 2 cosθ sinθ

So, above equation becomes,

R = (2H x 2 cosθ sinθ)/sin²θ

R = (4H cosθ)/sinθ

tanθ = R/4H

θ = tan⁻¹(R/4H)

Substitute 111 m for R and 72.3 m for H in the above equation.

θ = tan⁻¹( 111/ 4 x 72.3 )

θ = tan⁻¹(0.38)

θ = 20.99°

3 0

3 years ago

g A 39.0-kilogram child sits on a uniform seesaw of negligible mass; she is 2.60 m from the pivot point (or fulcrum). How far fr

Deffense [45]

Answer:

4.6091 meters

Explanation:

In this problem, to have equilibrium in the seesaw, we need the torque from one child to compensate the torque from the other child.

The torque is calculated by making the product of the mass and the distance to the pivot point.

So, the torque generated by the first child (T1) is equal to:

T1 = m1 * d1 = 39 * 2.6 = 101.4 Nm

To make equilibrium, we need the second child to generate the same torque (T2), so:

T2 = m2 * d2 = 22 * d2 = 101.4

d2 = 101.4 / 22 = 4.6091 m

The second child need to be at 4.6091 meters from the pivot point to be in equilibrium.

7 0

3 years ago

Write down the boiling point and freezing point of mercury an alcohol​

Write down the boiling point and freezing point of mercury an alcohol