Here's the formula for mechanical advantage.
It's very important, and you should memorize it:
Mechanical Advantage = (output force) divided by (input force) .
#1). Force that moves the object = output force = 550N
Force that it takes = input force = 200N
Use the formula:
(output force) divided by (input force) = 550N/200N = 2.75 .
#2).
#3).
#4).
#5).
#6).
#7).
#8).
#9).
#10).
All of the rest of the problems on the page tell you the input force
and the output force. They can be solved by using the same formula
to calculate the mechanical advantage, just like I did in #1).
I disagree with the first sentence of #11. But by the time you get there,
you'll be an expert in mechanical advantage, so you can investigate and
decide who's correct ... the sheet or me.
Answer:
A) The ball will roll forever in a straight path.
The molecular mass, in atomic mass unit, of aspartame would be 294 amu while the mass, in kg, of an aspartame molecule would be 0.294 kg
Aspartame has the chemical formula C14H18N2O5
C = 12, H = 1, N = 14, O = 16
(a) Molecular weight = (12x14) + (1x18) + (14x2) + (16x5)
= 168 + 18 + 28 + 80
= 294 amu
(b) Mass of 1 molecule of aspartame = mole x molar mass
= 1 x 294
= 294 g
Converting 294 g to kg = 294/1000
= 0.294 kg
More on mole and molar mass can be found here: brainly.com/question/6613610
I believe it is a closed circuit
Answer:
the speed of the car at the top of the vertical loop 
the magnitude of the normal force acting on the car at the top of the vertical loop 
Explanation:
Using the law of conservation of energy ;
The magnitude of the normal force acting on the car at the top of the vertical loop can be calculated as:
![F_{N} = \frac{mv^2_{top}}{R} \ - mg\\\\F_{N} = \frac{m(2.0 \sqrt{gR})^2}{R} \ - mg\\\\F_{N} = [(2.0^2-1]mg\\\\F_{N} = [(2.0)^2 -1) (50*10^{-3} \ kg)(9.8 \ m/s^2]\\\\](https://tex.z-dn.net/?f=F_%7BN%7D%20%3D%20%5Cfrac%7Bmv%5E2_%7Btop%7D%7D%7BR%7D%20%5C%20-%20mg%5C%5C%5C%5CF_%7BN%7D%20%3D%20%5Cfrac%7Bm%282.0%20%5Csqrt%7BgR%7D%29%5E2%7D%7BR%7D%20%5C%20-%20mg%5C%5C%5C%5CF_%7BN%7D%20%3D%20%5B%282.0%5E2-1%5Dmg%5C%5C%5C%5CF_%7BN%7D%20%3D%20%5B%282.0%29%5E2%20-1%29%20%2850%2A10%5E%7B-3%7D%20%5C%20kg%29%289.8%20%5C%20m%2Fs%5E2%5D%5C%5C%5C%5C)
