r₁ = distance of the point from the source = 43 km = 43000 m
I₁ = intensity of earthquake wave at distance "r₁" = 2.5 x 10⁶ W/m²
r₂ = distance of the point from the source = 1.5 km = 1500 m
I₂ = intensity of earthquake wave at distance "r₂" = ?
we know that , for a constant power , the intensity of wave is inversely proportional to the distance from the source .
I α 1/r² where I = intensity of wave , r = distance from source
hence we can write
I₁/I₂ = r₂²/r₁²
inserting the values
(2.5 x 10⁶) /I₂ = (1500/43000)²
I₂ = 2.1 x 10⁹ W/m²
From the formula, V=displacement/time
displacement/distance =velocity*time
distance=1200*2.5
distance=3*10³km
It a blue tectonic movement
Given that
Work = 600,000 J ,
distance(S) = 500 m ,
mass (m) = 250 Kg ,
Determine the velocity of car (v) = ?
We know that,
Work = Force × distance
=> Force = Work ÷ distance
= 600,000 ÷ 500
= 500 N .
Also Force F = m.a ; from Newtons II law
500 = 250 × a
a = 2 m/s.
<em>Final Velocity from the given formula </em>
V² = u² + 2.a.s
= 0 + 2 × 2 × 500
= \sqrt{2000}
<em> v = 44.7 m/s</em>
