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2 years ago

In an inelastic collision, as compared to an elastic collision, what is to be expected?.

1 answer:

3 0

The loss or conservation of kinetic energy is the difference between an elastic and an inelastic collision. Kinetic energy is not preserved in an inelastic collision, and it will change forms into sound, heat, radiation, or another form. The kinetic energy in an elastic collision is preserved and does not change forms.

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Calculate the acceleration of a helium nucleus (charge +2e, where e-electronic charge), when it enters an electric field of stre

konstantin123 [22]

Answer:

3.8 x 10^10 m/s^2

Explanation:

Charge, q = 2 e = 2 x 1.6 x 10^-19 C = 3.2 x 10^-19 C

Electric field strength, E = 790 N/C

mass of helium nucleus, m = 6.645 x 10^-27 Kg

the force due to electric filed on a charge particle is given by

F = q x E

Where, q be the charge on the charged particle and E be the strength of electric field.

By substituting the values

F = 3.2 x 10^-19 x 790

F = 2528 x 10^-19 N

According to the Newton's second law

F = m x a

Where, me be the mass and a be the acceleration

By substituting the values

$2528\times 10^{-19}=6.645\times 10^{-27}\times a$

a = 3.8 x 10^10 m/s^2

3 0

3 years ago

What is the speed of light?

Zielflug [23.3K]

The speed of light is 299,792,458 meters per second in vacuum,
somewhat less in any material. How much less depends on the material.

6 0

3 years ago

Isolating a variable in two equations is easiest when one of them has a coefficient of 1. Let's say we have the two equations 3A

xxTIMURxx [149]

Answer:

$B=3A-5$

Explanation:

<u>Variable Isolation</u>

It's a common practice when dealing with equations that we have to isolate one variable in terms of other variables and/or constants. The isolation of the variable usually implies adding, subtracting, multiplying or dividing by constants. The following example shows how to isolate the A:

$2A+3B=-4\\\\2A=-4-3B\\\\\displaystyle A=\frac{-4-3B}{2}$

We are required to find the equation where the variable has a coefficient of 1 and isolate it. The following equation fits into the description:

$3A-B=5$

Isolating B:

$B=3A-5$

3 0

3 years ago

1. An object is moving at 4.66 m/s when it accelerates at 5.66 m/s2 for a period of 2.35 s. The distance it moves in this time i

lesya [120]

Answer:

1. Distance, S = 26.58 meters

2. Acceleration of gravity, g = 58.60 m/s²

Explanation:

1. Given the following data;

Initial velocity = 4.66 m/s

Acceleration = 5.66 m/s²

Time = 2.35 seconds

To find the distance travelled by the object, we would use the second equation of motion;

S = ut + ½at²

Where;

S represents the displacement or height measured in meters.

u represents the initial velocity measured in meters per seconds.

t represents the time measured in seconds.

a represents acceleration measured in meters per seconds square.

Substituting into the equation, we have;

S = 4.66*2.35 + ½*5.66*2.35²

S = 10.951 + (2.83 * 5.5225)

S = 10.951 + 15.629

S = 26.58 meters

2. Given the following data;

Displacement (height) = 1.55 m

Time, t = 0.23 seconds

To find the acceleration of gravity, we would use the following formula;

Height = ½gt²

Substituting into the formula, we have;

1.55 = ½ * g * 0.23²

1.55 = ½ * g * 0.0529

1.55 = 0.02645g

Acceleration of gravity, g = 1.55/0.02645

Acceleration of gravity, g = 58.60 m/s²

5 0

3 years ago

A disk and a hoop roll down an inclined plane. the plane is inclined at an angle of 11 degrees from the horizontal. what is the

anygoal [31]

Hopefully this will help you.
Do the same for disc. Moment of Inertia of disc about its axis = MR²/2

6 0

3 years ago