Answer:
(-1, 10)
(2, 1)
(0, 7)
Step-by-step explanation:
Any points, that makes the equation of the function, f(x) = 7 - 3x, true, is a point that lies on the graph of the function.
Let's check each of the options.
Option 1: (-2, 1).
Plug in x = -2, f(x) = 1 into f(x) = 7 - 3x
1 = 7 - 3(-2)
1 = 7 + 6
1 = 13 (this is not true)
Thus, (-2, 1) is not a point that lies on the graph of the function.
Option 2: (-1, 10).
Plug in x = -1, f(x) = 10 into f(x) = 7 - 3x
10 = 7 - 3(-1)
10 = 7 + 3
10 = 10 (this is true)
Thus, (-1, 10) is a point that lies on the graph of the function.
Option 3: (2, 1).
Plug in x = 2, f(x) = 1 into f(x) = 7 - 3x
1 = 7 - 3(2)
1 = 7 - 6
1 = 1 (this is true)
Thus, (2, 1) is a point that lies on the graph of the function.
Option 4: (0, 7).
Plug in x = 0, f(x) = 7 into f(x) = 7 - 3x
7 = 7 - 3(0)
7 = 7 - 0
7 = 7 (this is true)
Thus, (0, 7) is a point that lies on the graph of the function.
Option 5: (1, 5).
Plug in x = 1, f(x) = 5 into f(x) = 7 - 3x
5 = 7 - 3(1)
5 = 7 - 3
5 = 4 (this is not true)
Thus, (1, 5) is NOT a point that lies on the graph of the function.
