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3 years ago

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Debbie touches the metal doorknob to her bedroom at 7 a.m. and feels a static electric shock. In the afternoon, Debbie comes bac

k and touches the doorknob again, but she experiences no shock.

1 answer:

AleksandrR [38]3 years ago

5 0

Answer:

she had socks one and was shuffeling so she had static

Explanation:

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Celina has a water sample that’s contaminated with salt and microorganisms. Which method should she use to purify the water?

TEA [102]

Answer:

Reverse Osmosis and UV Treatment

Explanation:

Reverse Osmosis, commonly known as RO, process is very effective in removing salt content from water. This process is known as desalination. IN RO, a partially permeable membrane is used to remove unwanted molecules, ions, and large particles. RO will take care of both desalination and purification of water.

Further UV treatment can be done to kill any remaining microorganisms as these microorganisms can not withstand UV radiation.

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3 years ago

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A blue textbook will _____<br> green light. A) emit B) reflect C) absorb D) transmit

Tanzania [10]

The answer is C. An object that appears a certain color reflects the light frequency that corresponds to that color, and it absorbs all the other frequencies in the visible light spectrum. An orange absorbs all of the frequencies but orange. A BLUE TEXTBOOK ABSORBS all of the frequencies INCLUDING GREEN except for BLUE.

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3 years ago

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In Anchorage, collisions of a vehicle with a moose are so common that they are referred to with the abbreviationMVC. Suppose a 1

lara31 [8.8K]

Answer:

Part a)

$f = \frac{8}{9}$

Part b)

$f = \frac{120}{169}$

Part c)

So from above discussion we have the result that energy loss will be more if the collision occurs with animal with more mass

Explanation:

Part a)

Let say the collision between Moose and the car is elastic collision

So here we can use momentum conservation

$m_1v_{1i} = m_1v_{1f} + m_2v_{2f}$

$1000 v_o = 1000 v_{1f} + 500 v_{2f}$

also by elastic collision condition we know that

$v_{2f} - v_{1f} = v_o$

now we have

$2v_o = 2v_{1f} + v_o + v_{1f}$

now we have

$v_{1f} = \frac{v_o}{3}$

Now loss in kinetic energy of the car is given as

$\Delta K = \frac{1}{2}m(v_o^2 - v_{1f}^2)$

$\Delta K = \frac{1}{2}m(v_o^2 - \frac{v_o^2}{9})$

so fractional loss in energy is given as

$f = \frac{\Delta K}{K}$

$f = \frac{\frac{4}{9}mv_o^2}{\frac{1}{2}mv_o^2}$

$f = \frac{8}{9}$

Part b)

Let say the collision between Camel and the car is elastic collision

So here we can use momentum conservation

$m_1v_{1i} = m_1v_{1f} + m_2v_{2f}$

$1000 v_o = 1000 v_{1f} + 300 v_{2f}$

also by elastic collision condition we know that

$v_{2f} - v_{1f} = v_o$

now we have

$10v_o = 10v_{1f} + 3(v_o + v_{1f})$

now we have

$v_{1f} = \frac{7v_o}{13}$

Now loss in kinetic energy of the car is given as

$\Delta K = \frac{1}{2}m(v_o^2 - v_{1f}^2)$

$\Delta K = \frac{1}{2}m(v_o^2 - \frac{49v_o^2}{169})$

so fractional loss in energy is given as

$f = \frac{\Delta K}{K}$

$f = \frac{\frac{60}{169}mv_o^2}{\frac{1}{2}mv_o^2}$

$f = \frac{120}{169}$

Part c)

So from above discussion we have the result that energy loss will be more if the collision occurs with animal with more mass

8 0

3 years ago

Mixtures that appear to be homogeneous but actually contain particles that are intermediate in size between solutions and suspen

Yakvenalex [24]

2 is the answer hope you have a great day

3 0

3 years ago

You are hiking along a trail in a wide, dry canyon where the outdoor temperature is T = 29.5° C. To determine how far you are aw

STALIN [3.7K]

Answer:

<em>The canyon is approximately 314 meters away</em>

Explanation:

<u>Speed of Sound</u>

If we emit sounds in an open space where a large obstacle (like a mountain) is expected to return the sounds, then it will travel forth and back at a given speed for a certain time. We can assume the speed of sound is constant, so we could know the approximate distance of the mountain (or canyon in our case) by the known formula.

$x=v_st$

Where $v_s$ is the speed of sound and t is half the time we hear our echo.

The speed of sound in m/s can be calculated from the approximate formula in terms of the temperature T in degrees Celsius

$v_s=331.3+0.606T$

We have $T=29.5^oC$ , so

$v_s=331.3+0.606(29.5)$

$v_s=349.177\ m/s$

Let's compute x, for t=1.8/2=0.9 seconds

$x=v_st=(349.177)(0.9)$

$x=314.26\ m$

The canyon is approximately 314 meters away

7 0

3 years ago