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Natalija [7]
2 years ago
7

The scattering of dissolved particles evenly is called

Physics
1 answer:
FrozenT [24]2 years ago
5 0

Answer:

the process of that happening is called Dissolving

the substance that is dissolved is called

Solute

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14 kilometers per hour to meters per second
Alina [70]

Answer:

About 3.88 meters per second

Explanation:

14km= 14,000m

14,000m per hour

so 14,000 ÷ 60= 233.33 meters per minute

233.33÷60=3.88 meters per second

3 0
3 years ago
If element X has 17 protons, how many electrons does it have?
OleMash [197]
18 electrons because protons minus the atomic mass so it would be 35-17 which gives you 18.
3 0
3 years ago
Scientific models have two basic types. Please select the best answer from the choices provided T F
zubka84 [21]

Answer:

Scientific models have two basic types. FALSE.

Hoped I helped

3 0
3 years ago
Which statement best describes the difference between a substance with a pH of 3.0 and a substance with a pH of 6.0?
satela [25.4K]

The statement best describes the difference between a substance with a pH of 3.0 and a substance with a pH of 6.0 is - The substance with the lower pH has 1,000 times as many hydrogen ions per volume of water.

pH is the scale or measure for the substance about its acidic or basic strength. It ranges from 0 to 6.9 which is acidic and 7.1 to 14 which is basic.

Acidic substance has high concentration of Hydrogen ions whereas, basic substance has low concentration of hydrogen ions, however for the OH⁻ ions it is reverse.

  • Concentration of hydrogen ions is inversely related to its pH
  • More hydrogen ions present, the lower the pH
  • The fewer hydrogen ions, the higher the pH We know,

pH = -log(H^{+}) then,  

=> 3 = -log (H^{+})

=> H^{+} =  (for pH = 3)  

=> pH = -log(H^{+})

=> 6 = -log (H^{+})

=> H^{+} = 10^{-6} (for pH = 6)

 Thus, The substance with the lower pH (3) has 1000 times as many hydrogen ions per volume of water.

Learn more about pH scale:

brainly.com/question/1596421

7 0
3 years ago
A 5.0-kg block of wood is placed on a 2.0-kg aluminum frying pan. How much heat is required to raise the temperature of both the
Shalnov [3]

Heat required to raise the temperature of a given system is

Q = ms\Delta T

here we know that

m = mass

s = specific heat capacity

\Delta T = change in temperature

now as we know that

mass of wood = 5 kg

mass of aluminium pan = 2 kg

change in temperature = 45 - 20 = 25 degree C

specific heat capacity of wood = 1700 J/kg C

specific heat capacity of aluminium = 900 J/kg C

now here we will find the total heat to raise the temperature of both

Q = m_1s_1\Delta T_1 + m_2s_2\Delta T_2

Q = 5 * 1700 * 25 + 2 * 900 * 25

Q = 212500 + 45000

Q = 257500 J

So heat required to raise the temperature of the system is 257500 J

4 0
3 years ago
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