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Natalija [7]
2 years ago
7

The scattering of dissolved particles evenly is called

Physics
1 answer:
FrozenT [24]2 years ago
5 0

Answer:

the process of that happening is called Dissolving

the substance that is dissolved is called

Solute

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Sound enters the ear, travels through the auditory canal, and reaches the eardrum. The auditory canal is approximately a tube op
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Answer: An organ pipe is open at both ends. It is producing sound at its third harmonic, the frequency of which is 262 Hz. The speed of sound is 343 m/s. What is the length of the pipe?

Explanation: thanks for asking

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2 years ago
Find the velocity and distance travelled of a car that is accelerating at 3 m/s2 for 4 seconds.
marta [7]

Explanation:

Given:

v₀ = 0 m/s

a = 3 m/s²

t = 4 s

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Δx = v₀ t + ½ at²

Δx = (0 m/s) (4 s) + ½ (3 m/s²) (4 s)²

Δx = 24 m

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A boy jumps from a wall 3m high. What is an estimate of the change in momentum of the boy when he lands without rebounding?
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The answer is D. Because the boy jump 3 high
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3 years ago
Lori’s family is on a road trip. They split their drive into the five legs listed in the table. Find the average velocity for ea
PIT_PIT [208]
Average velocity is displacement  divided by time elapsed; Δv/Δt

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3 0
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Review. As an astronaut, you observe a small planet to be spherical. After landing on the planet, you set off, walking always st
anyanavicka [17]

To find the mass of the planet we will apply the relationship of the given circumference of the planet with the given data and thus find the radius of the planet. From the kinematic equations of motion we will find the gravitational acceleration of the planet, and under the description of this value by Newton's laws the mass of the planet, that is,

The circumference of the planet is,

\phi = 25.1m

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\phi = 2\pi r

r = \frac{25}{2\pi}

r = 3.9788km

Using second equation of motion

x = \frac{1}{2} at^2

Replacing the values given,

1.4 = \frac{1}{2} a (29.2)^2

Rearranging and solving for 'a' we have,

a = 0.003283m/s^2

Using the value of acceleration due to gravity from Newton's law we have that

a = \frac{GM}{r^2}

Here,

r = Radius of the planet

G = Gravitational Universal constant

M = Mass of the Planet

\frac{(6.67*10^{-11})*M}{(3.9788*10^3)^2} = 0.003283

M = 7.79201*10^{14}kg

Therefore the mass of this planet is 7.79201*10^{14}kg

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3 years ago
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