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Maurinko [17]
3 years ago
15

Someone help with this will mark brainliest

Chemistry
1 answer:
jenyasd209 [6]3 years ago
4 0

Answer:

The main difference between emission and absorption spectra is that an emission spectrum has different coloured lines in the spectrum, whereas an absorption spectrum has dark-coloured lines in the spectrum.l

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Please help me with these?
Julli [10]

Question 5 is the second one.


8 0
3 years ago
A drag racing vehicle travels from 0 to 100 mph in 5 seconds north.what is the acceleration
arsen [322]

100mph = 100m/h

= 100m/h * 1 h/3600sec

= 0.028m/sec

= 0.028m/sec /5sec

= 0.055m/sec^2

6 0
4 years ago
Which of the following is a homogeneous mixture?A) Molten ironB) Stainless steelC) Trail mixD) Water
ehidna [41]

Answer:

B) Stainless steel

Explanation:

Homogeneous mixture  -

It refers to the composition of various substance , which leads to a mixture of complete uniform composition , i.e. , the ratio of each and every component of the mixture is constant all over the mixture , is referred to as a homogeneous mixture.

For example ,

In the solution of sugar and water , where 1 tablespoon of sugar is dissolved in 100 mL of water ,

The ratio of sugar and water remains constant all over the mixture.

Hence, from the given options the homogeneous mixture is B) Stainless steel .

5 0
3 years ago
Match each term with its definition.
stiks02 [169]
(TOP TO BOTTOM)
C
F
D
A
E
B
5 0
3 years ago
Phosgene, COCl2, gained notoriety as a chemical weapon in World War I. Phosgene is produced by the reaction of carbon monoxide w
jek_recluse [69]

The question is incomplete, here is the complete question:

Phosgene, COCl_2, gained notoriety as a chemical weapon in World War I. Phosgene is produced by the reaction of carbon monoxide with chlorine:  

CO(g)+Cl_2(g)\rightleftharpoons COCl_2(g)

The value of K_c for this reaction is 5.79 at 570 K. What are the equilibrium partial pressures of the three gases if a reaction vessel initially contains a mixture of the reactants in which p_{CO}=p_{Cl_2}=0.265atm and p_{COCl_2}=0.000atm ?

<u>Answer:</u> The equilibrium partial pressure of CO, Cl_2\text{ and }COCl_2 is 0.257 atm, 0.257 atm and 0.008 atm respectively.

<u>Explanation:</u>

The relation of K_c\text{ and }K_p is given by:

K_p=K_c(RT)^{\Delta n_g}

K_p = Equilibrium constant in terms of partial pressure

K_c = Equilibrium constant in terms of concentration = 5.79

\Delta n_g = Difference between gaseous moles on product side and reactant side = n_{g,p}-n_{g,r}=1-2=-1

R = Gas constant = 0.0821\text{ L. atm }mol^{-1}K^{-1}

T = Temperature = 570 K

Putting values in above equation, we get:

K_p=5.79\times (0.0821\times 570)^{-1}\\\\K_p=0.124

We are given:

Initial partial pressure of CO = 0.265 atm

Initial partial pressure of chlorine gas = 0.265 atm

Initial partial pressure of phosgene = 0.00 atm

The given chemical equation follows:

                      CO(g)+Cl_2(g)\rightleftharpoons COCl_2(g)

<u>Initial:</u>            0.265      0.265

<u>At eqllm:</u>        0.265-x    0.265-x        x

The expression of K_p for above equation follows:

K_p=\frac{p_{COCl_2}}{p_{CO}\times p_{Cl_2}}

Putting values in above equation, we get:

0.124=\frac{x}{(0.265-x)\times (0.265-x)}\\\\x=0.0082,8.59

Neglecting the value of x = 8.59 because equilibrium partial pressure cannot be greater than initial pressure

So, the equilibrium partial pressure of CO = (0.265-x)=(0.265-0.008)=0.257atm

The equilibrium partial pressure of Cl_2=(0.265-x)=(0.265-0.008)=0.257atm

The equilibrium partial pressure of COCl_2=x=0.008atm

Hence, the equilibrium partial pressure of CO, Cl_2\text{ and }COCl_2 is 0.257 atm, 0.257 atm and 0.008 atm respectively.

6 0
3 years ago
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