distance to the star Betelgeuse: 640 ly
As we know that

also we know that


So the distance of Betelgeuse = 640 ly

distance to the star VY Canis Majoris: 


distance to the galaxy Large Magellanic Cloud: 49976 pc


now we have


distance to Neptune at the farthest: 4.7 billion km

now the order of distance from least to greatest is as following
1. distance to Neptune at the farthest
2. distance of Betelgeuse
3. distance to the star VY Canis Majoris
4. distance to the galaxy Large Magellanic Cloud
In a displacement/time graph, the slope of the line is equal to the velocity
D.all of the above is the answer for this question
Emissivityis a measure of how much thermal radiation a body emits to its environment. On the other hand we have that reflectivity is a measure of how much is reflected, and transmissivity is a measure of how much passes through the object. If a body is required to be ideally reflective to its maximum efficiency, the body should NOT have the property of transmissivity or emissivity. Therefore it should be 0 its emittivity.
Correct answer would be A : ZERO.
"<span>a layer in the earth's stratosphere at an altitude of about 6.2
miles (10 km) containing a high concentration of ozone, which absorbs
most of the ultraviolet radiation reaching the earth from the sun."
Hope this helps!
</span>