Answer:
w_cycle = 13.68 KJ / cycle
Explanation:
Given:
- Steady power out-put W_out = 15.5 hp
- System executes 50 cycles/min
Find:
Determine the amount of work that is delivered during each cycle in kilo-joules
Solution:
- First we will convert the steady output into KW as follows:
W_out = 15.5 hp
The conversion factor is 1.36 KW per hp.
W_out = 15.5 [hp] * [KW] / 1.36 [hp]
W_out = 11.4 [KW] or [KJ/s]
- Given that there are 50 cycles in 60 sec. We will use direct proportionality to calculate the number of cycles per second:
50 cycles -----------> 60 s
x cycles -----------> 1 s
x = 50/60 = 0.8333 cycles /s
- Next we will compute the amount of work done per cycle:
w_cycle = W_out / x
w_cycle = 11.4 [KJ/s] * [s] / 0.8333 [cycles]
w_cycle = 13.68 KJ / cycle
