Helppp me yfovkhovhivy

A meter stick whose mass is 290 grams lies on ice. You pull at one end of the meter stick, at right angles to the stick, with a

katen-ka-za [31]

Answer

given,

mass of the stick = 290 grams = 0.29 Kg

Force on the stick on one side = F = 9 N

force acting perpendicular to stick.

magnitude of acceleration

rate of change of angular momentum is equal to Force

rate of change of angular momentum = 9 N

F = m a

$a = \dfrac{F}{m}$

$a = \dfrac{9}{0.29}$

a = 31.034 m/s²

Direction of motion will in the direction of force application or in the direction of change of velocity

5 0

4 years ago

. An experimental rocket plane lands on skids on a dry lake bed. If it’s traveling at 80.0 m/s when it touches down, how far doe

kobusy [5.1K]

Answer:

1. A substance that can be separated into two or more substances only by a chemical change is a(n) _____.

solution

element

mixture

compound

2.

Which of the following materials is a substance?

air

gasoline

stainless steel

silver

3.

The first figure in a properly written chemical symbol always is _____.

boldfaced

capitalized

italicized

underlined

4.

Which of the following represents a compound?

H

H-3

H2O

O-16

5. What do chemical symbols and formulas represent, respectively?

elements and compounds

atoms and mixtures

compounds and mixtures

elements and ions

Explanation:

5 0

2 years ago

On august 10, 1972, a large meteorite skipped across the atmosphere above the western united states and western canada, much lik

RUDIKE [14]

(a)
The velocity of the meteorite just before hitting the ground is:
$v=20 km/s=20000 m/s$
The loss of energy of the meteorite corresponds to the kinetic energy the meteorite had just before hitting the ground, so:
$\Delta K = \frac{1}{2}mv^2= \frac{1}{2}(3.4 \cdot 10^6 kg)(20000 m/s)^2=6.8 \cdot 10^{14}J$

(b) 1 megaton of tnt is equal to $1 MT=4.2 \cdot 10^{15}J$
To find to how many megatons the meteorite energy loss $\Delta E$
corresponds, we can set the following proportion
$1 MT: 4.2 \cdot 10^{15}J=x: \Delta E$
And so we find
$x= \frac{\Delta E}{4.2 \cdot 10^{15}J} = \frac{6.8 \cdot 10^{14}J }{4.2 \cdot 10^{15}J} =0.162 MT$
So, 0.162 megatons.

(c) 1 Hiroshima bomb is equivalent to 13 kilotons (13 kT). The impact of the meteorite had an energy of $\Delta E=0.162 MT=162 kT$ . So, to find to how many hiroshima bombs it corresponds, we can set the following proportion:
$1:13 kT=x:162 kT$
And so we find
$x= \frac{162 kT}{13 kT}=12.46$
So, the energy released by the impact of the meteorite corresponds to the energy of 12.46 hiroshima bombs.

7 0

4 years ago

Septum: Left and right atrium: Pacemaker: Left and right ventricles: Valves:

hammer [34]

Can you define the question further.

This may help with your answer:

Tricuspid valve. This valve is located between the right atrium and the right ventricle.
Pulmonary valve. The pulmonary valve is located between the right ventricle and the pulmonary artery.
Mitral valve. This valve is located between the left atrium and the left ventricle. It has only 2 leaflets.
Aortic valve. The aortic valve is located between the left ventricle and the aorta

4 0

3 years ago

A wave is traveling in a string at 58 m/s. when the tension is then increased 17%, what will be the resulting wave speed?

Zepler [3.9K]

the resulting wave speed=62.7 m/s

Explanation:

The speed of a wave is given by

v= $\sqrt{\frac{T}{\mu} }$