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3 years ago

What are the subsystems of a machine that pops a balloon?

Physics

1 answer:

mariarad [96]3 years ago

3 0

Answer:

The answer is simple machine!!

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11. Distinguish between solid and liquid states of matter in terms of intermolecular forces

solmaris [256]

Answer:

In solid it is high because the molecules are closely packed.

In liquid it is lesser than solids as they are loosely

packed.

In gas it is least because they are very loosely packed

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1 year ago

18. Write conversion factors (as ratios) for the number of:

Romashka [77]

Answer:

Conversion tables show:

1 m = 1.09361 yds

1 Lit = .26418 gal = 1.05672 qt or 1 qt = .944632 Lit

1 lb = .45359 kg = 2.2046 Lbs / Kg

So X yds = X m * 1.09361 yds / m = 1.09361 * X yds

Likewise X Lit = X qt / 1.05672 qt/ Lit = X / 1.05672 Lit = .94632 X Lit

So X Lbs = X kg * 2.2046 Lbs / Kg = 2.2046 Lbs

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3 years ago

What happens to the change in the value of the speed as you increased the amount of force applied on your

nataly862011 [7]

The change of speed is proportional to the Force. If you double the Force, you double the change of speed.

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3 years ago

Why is it advisable to wear long sleeves when a student works in a chemistry lab

love history [14]

So then if they do spill the chemical then it gets on their cloths and not on then it dosen"t harm them instead it ruins their shirt.

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3 years ago

Read 2 more answers

g You drop a 3.6-kg ball from a height of 3.5 m above one end of a uniform bar that pivots at its center. The bar has mass 9.9 k

Salsk061 [2.6K]

Answer:

h = 3.5 m

Explanation:

First, we will calculate the final speed of the ball when it collides with a seesaw. Using the third equation of motion:

$2gh = v_f^2 - v_i^2\\$

where,

g = acceleration due to gravity = 9.81 m/s²

h = height = 3.5 m

vf = final speed = ?

vi = initial speed = 0 m/s

Therefore,

$(2)(9.81\ m/s^2)(3.5\ m) = v_f^2 - (0\ m/s)^2\\v_f = \sqrt{68.67\ m^2/s^2}\\v_f = 8.3\ m/s$

Now, we will apply the law of conservation of momentum:

$m_1v_1 = m_2v_2$

where,

m₁ = mass of colliding ball = 3.6 kg

m₂ = mass of ball on the other end = 3.6 kg

v₁ = vf = final velocity of ball while collision = 8.3 m/s

v₂ = vi = initial velocity of other end ball = ?

Therefore,

$(3.6\ kg)(8.3\ m/s)=(3.6\ kg)(v_i)\\v_i = 8.3\ m/s$

Now, we again use the third equation of motion for the upward motion of the ball:

$2gh = v_f^2 - v_i^2\\$

where,

g = acceleration due to gravity = -9.81 m/s² (negative for upward motion)

h = height = ?

vf = final speed = 0 m/s

vi = initial speed = 8.3 m/s

Therefore,

$(2)(9.81\ m/s^2)h = (0\ m/s)^2-(8.3\ m/s)^2\\$

6 0

2 years ago