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3 years ago

Could a 3 ion of aluminum be made by adding three protons to an aluminum atom

1 answer:

7 0

Protons cannot be so easily added to an atom, so this method cannot be used to produce ions. Protons are found in the nucleus which is held together by strong forces. This means that its structure is not easily changed. Bombarding it with a proton may even cause its decay, just as in nuclear fission a nucleus is bombarded with neutrons.

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Determine whether or not the equation below is balanced. If it isn’t balanced, write the balanced form. Also, identify the react

Natasha_Volkova [10]

Answer:

Explanation:

There's no equation attached. What equation is it?

5 0

3 years ago

Read 2 more answers

Are particles in gas close together

Vesna [10]

Answer:

Solid particles are close together not gas particles

6 0

2 years ago

Does anyone know how to do this? the solubility of barium carbonate, BaCO3, is 0.0100 g/L. Its molar mass is 197.3 g/mol. What i

g100num [7]

It's simple, just follow my steps.

1º - in 1 L we have $0.0100~g$ of $BaCO_3$

2º - let's find the number of moles.

$\eta=\frac{m}{MM}$

$\eta=\frac{0.0100}{197.3}$

$\boxed{\boxed{\eta=5.07\times10^{-5}~mol}}$

3º - The concentration will be

$C=5.07\times10^{-5}~mol/L$

But we have this reaction

$BaCO_3\rightleftharpoons Ba^{2+}+CO_3^{2-}$

This concentration will be the concentration of $Ba^{2+}~~and~~CO_3^{2-}$

$K_{sp}=\frac{[Ba^{2+}][CO_3^{2-}]}{[BaCO_3]}$

considering $[BaCO_3]=1~mol/L$

$K_{sp}=[Ba^{2+}][CO_3^{2-}]$

and

$[Ba^{2+}]=[CO_3^{2-}]=5.07\times10^{-5}~mol/L$

We can replace it

$K_{sp}=(5.07\times10^{-5})*(5.07\times10^{-5})$

$K_{sp}\approx25.70\times10^{-10}$

Therefore the $K_{sp}$ is:

$\boxed{\boxed{\boxed{K_{sp}\approx2.57\times10^{-11}}}}$

4 0

3 years ago

Read 2 more answers

Consider the reaction below.

saw5 [17]

This answer to this question is a rule that is applied to any reaction taken at dynamic equilibrium, with respect to 500 K. In other words, you can say that this reaction is of no use to us -

In a chemical equilibrium, it is known that the forward and reverse reactions occur at equal rates. At this point the concentrations of products and reactants remain constant, or in other words do not change

Solution = Option C

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2 years ago

How to calculate percentage change in mass

blondinia [14]

In order to find the percentage change in mass, you must divide Change in Mass by Initial Mass. After that, you divide the change in mass by the initial mass of your substance.

This calculation shows what proportion of the initial mass changed. To find the percent change, simply multiply this number by 100

3 0

3 years ago