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Nadya [2.5K]
3 years ago
11

Suppose a radioactive substance has a half-life of 1000 years. What fraction will be left after 1000 years?

Mathematics
2 answers:
Nezavi [6.7K]3 years ago
5 0

Answer:

1/2

Step-by-step explanation:

so if u do the waffalineneh times by arcimate it would equivently be the answer on top

salantis [7]3 years ago
3 0

Answer:

\frac{1}{2}

Step-by-step explanation:

The half life is the amount of time it takes a substance to decay to half of its original amount.

Since the radioactive substance has a half life of 1000 years, there will be half of it left after 1000 years.

So, the fraction that will be left after 1000 years is \frac{1}{2}

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assume that when adults with smartphones are randomly selected 15 use them in meetings or classes if 15 adult smartphones are ra
Tanzania [10]

Answer:

The probability that at least 4 of them use their smartphones is 0.1773.

Step-by-step explanation:

We are given that when adults with smartphones are randomly selected 15% use them in meetings or classes.

Also, 15 adult smartphones are randomly selected.

Let X = <em>Number of adults who use their smartphones</em>

The above situation can be represented through the binomial distribution;

P(X = r) = \binom{n}{r}\times p^{r} \times (1-p)^{n-r} ; n = 0,1,2,3,.......

where, n = number of trials (samples) taken = 15 adult smartphones

           r = number of success = at least 4

           p = probability of success which in our question is the % of adults

                 who use them in meetings or classes, i.e. 15%.

So, X ~ Binom(n = 15, p = 0.15)

Now, the probability that at least 4 of them use their smartphones is given by = P(X \geq 4)

P(X \geq 4) = 1 - P(X = 0) - P(X = 1) - P(X = 2) - P(X = 3)

= 1- \binom{15}{0}\times 0.15^{0} \times (1-0.15)^{15-0}-\binom{15}{1}\times 0.15^{1} \times (1-0.15)^{15-1}-\binom{15}{2}\times 0.15^{2} \times (1-0.15)^{15-2}-\binom{15}{3}\times 0.15^{3} \times (1-0.15)^{15-3}

= 1- (1\times 1\times 0.85^{15})-(15\times 0.15^{1} \times 0.85^{14})-(105 \times 0.15^{2} \times 0.85^{13})-(455 \times 0.15^{3} \times 0.85^{12})

= <u>0.1773</u>

3 0
3 years ago
Jeanette's salary is 25000 a year she gets a 4% raise annually, how much will she have after 7 years
Mars2501 [29]
25,000 x .04 = 1000 a year......
so 7,000 after 7 years

So, in 7 years she'll be making 32,000 a year
8 0
3 years ago
Read 2 more answers
Can someone please just tell me how to answer any question like this PLEASE!
rjkz [21]

Answer:after multiplying , u then count the number of decimal places in the question and fix it in the answer,it should be from the right  to the left  

Step-by-step explanation:

43644+65466=698304

Then=6.98304

5 0
2 years ago
<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B128%7D%20" id="TexFormula1" title=" \sqrt{128} " alt=" \sqrt{128} " align="absmid
mars1129 [50]

Answer:

Step-by-step explanation:

I don't know what you mean by formula but I will simplify the surd for you.

\sqrt{128} = \sqrt{64(2)} = 8\sqrt{2}

8 0
3 years ago
ALGEBRA HELP PLEASE?!
ale4655 [162]
I think A is the answer .
8 0
3 years ago
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