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2 years ago

Answer the discussion question in complete sentences:

Physics

1 answer:

zhuklara [117]2 years ago

3 0

Earth is divided into two hemispheres/coast. Which is south, north, east, and west.
California is west coast.

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What do you mean by kinetic energy and potential energy ?

Verizon [17]

Kinetic Energy of an object is the measure of the work an object can do by virtue of its motions..

Formula - KE = 1/2 mv^2

Where KE is the kinetic energy, m is the body’s mass, and v is the body’s velocity.

Potential energy is the stored energy in any object or system by virtue of its position or arrangement of parts..

Formula - W = mgh

Where,

. m is the mass in kilograms

. g is the acceleration due to gravity

. h is the height in meters

Hope it helpz~ uh..

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1 year ago

The slope of the following graph represents

guajiro [1.7K]

Answer:

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3 years ago

Is there a definite end to our atmosphere?

Irina18 [472]

There is no definite end to earths atmosphere, but technically the border between the outer space and earth gets thinner as you move up from the earths surface. The Karman line is the closest definition there is which describes the end of the earth's atmosphere, it is 100 km above earth's sea level at approximately 1.56 % of total earth's radius. This describes the boundary between the outer space and the atmosphere.

7 0

3 years ago

Which of the following is not an ethical consideration of social research?

laiz [17]

I belive it it is C, using research to reform society

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3 years ago

Read 2 more answers

A person's prescription for her new bifocal glasses calls for a refractive power of -0.450 diopters in the distance-vision part,

Angelina_Jolie [31]

Answer:

Far point of the eye is 22.24 m

Far point of the eye is 0.4 m

Explanation:

$\frac{1}{f}=-0.045$

Object distance = u

Image distance = v

Lens equation

$\frac{1}{f}=\frac{1}{u}+\frac{1}{v}\\\Rightarrow \frac{1}{f}-\frac{1}{u}=\frac{1}{v}\\\Rightarrow \frac{1}{v}=-0.045-\frac{1}{\infty}\\\Rightarrow \frac{1}{v}=\frac{1}{-0.045}\\\Rightarrow v=-22.22\ m$

Far point

$|v|+\text{Position from eye}\\ =|-22.22|+0.02\\ =22.24\ m$

Far point of the eye is 22.24 m

Object distance = u = 0.25-0.02 = 0.23 m

$\frac{1}{f}=1.75$

$\frac{1}{f}=\frac{1}{u}+\frac{1}{v}\\\Rightarrow \frac{1}{f}-\frac{1}{u}=\frac{1}{v}\\\Rightarrow \frac{1}{v}=1.75-\frac{1}{0.23}\\\Rightarrow v=-0.38\ m$

Near point

$|v|+\text{Position from eye}\\= |-0.38|+0.02\\ =0.4\ m$

Far point of the eye is 0.4 m

7 0

3 years ago