The resulting change in momentum of the system will be +18.6 Ns. The momentum is conserved.
<h3>What is the law of conservation of momentum?</h3>
According to the law of conservation of momentum, the momentum of the body before the collision is always equal to the momentum of the body after the collision.
The given data in the problem is;
m is the mass =6.0 kg
t is the time interval=2 second
From Newton's second law;
From the graph;
The change in the momentum is;
Hence, the resulting change in momentum of the system will be +18.6 Ns.
To learn more about the law of conservation of momentum, refer;
brainly.com/question/1113396
#SPJ1
Answer:
The answer cannot be determined.
Explanation:
The energy of the diver when he hits the pool will be equal to its potential energy 
, and for the temperature of the pool to rise up, this energy has to be converted into the heat energy of the pool.
The change in temperature 
then will be
Where m is the mass of water in the pool, c is the specific heat capacity of water, and 
is the added heat which in this case is the energy of the diver.
Since we do not know the mass of the water in the pool, we cannot make this calculation.
Acceleration is the rate of change of velocity
To define acceleration, We need to know more about motion.
Motion: This can be defined as the change in position of a body from one point to another. When an object accelerates, it undergoes motion.
<u>Definition</u>
Acceleration can be defined as the rate of change of velocity. The S.I unit of acceleration is meter-per-squared seconds. (m/s²)
The formula of acceleration is
- a = (v-u)/t................. Equation 1
⇒ Where:
- a = acceleration
- u = initial velocity
- v = final velocity
- t = time
Hence, Acceleration is the rate of change of velocity
Learn more about acceleration here: brainly.com/question/605631
Melting: as mantle material rise toward the divergent plate boundary the pressure is reduced which causes melting
Answer:
m = 14*26 = 364
Explanation:
overall magnification is given as m
mo magnification of objective lens
me magnification of EYE lens
where mo is given as
and me as
d is distant of distinct vision = 25.0 cm for normal eye
fe = focal length of eye piece
focal length of objective lense is 0.140 cm
we know that
m = 14*26 = 364
