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Anna11 [10]
3 years ago
11

What is the molarity of a solution when 2.75 g of NaCl is dissolved in 1100 mL of solution?

Chemistry
1 answer:
earnstyle [38]3 years ago
4 0

Answer:

Explanation:

0.25 M

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Easy question, need help
jeka94

Answer: B= 210 amps

Explanation:

175

0.75 so you divide it so the answer it 210

since first you find for one

then you multiply 0.75 to the answer you get

Hope this helps :)

8 0
3 years ago
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Which element(s) are not balanced in this equation?
poizon [28]
The correct response is A. Only the Fe is unbalanced.
6 0
3 years ago
Explain how you can convert from the number of representative particles of a substance to moles of that substance.
Scrat [10]

Answer:

  • the number of representative contain in 1 mol of a substance equals to 6.o2x10^23 particles.
8 0
3 years ago
Question 12 (1 point)
Vinvika [58]

Answer:

Option c. Neutral

Explanation:

Only neutral solution gives a green colouration to a pH paper

8 0
3 years ago
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The empirical formula of a compound is CH2O and its molecular weight is 90.09 g/mol. Determine the molecular formula.
Pachacha [2.7K]

Answer : The molecular formula of the compound will be, C_{3}H_{6}O_3

Explanation :

Empirical formula : It is the simplest form of the chemical formula which depicts the whole number of atoms of each element present in the compound.  

Molecular formula : it is the chemical formula which depicts the actual number of atoms of each element present in the compound.  

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is :

n=\frac{\text{molecular mass}}{\text{empirical mass}}

As we are given that the empirical formula of a compound is CH_2O and the molar mass of compound is, 90.09 gram/mol.

The empirical mass of CH_2O = 1(12) + 2(1) + 1(16) = 30 g/eq

n=\frac{\text{molecular mass}}{\text{empirical mass}}

n=\frac{90.09}{30}=3

Molecular formula = (CH_2O)_n=(CH_2O)_3=C_{3}H_{6}O_3

Thus, the molecular formula of the compound will be, C_{3}H_{6}O_3

7 0
4 years ago
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