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Anna11 [10]
3 years ago
11

What is the molarity of a solution when 2.75 g of NaCl is dissolved in 1100 mL of solution?

Chemistry
1 answer:
earnstyle [38]3 years ago
4 0

Answer:

Explanation:

0.25 M

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Write the reaction from the word equation and then balence the equation
Mars2501 [29]
<h3>Answer:</h3>

Ni + Pb(NO₃)₂ → Ni(NO₃)₃ + Pb

<h3>Explanation:</h3>

We are required to write a balanced equation from the word equation;

  • Nickel reacts with lead nitrate (II) to produce nickel(III) nitrate and lead
  • The equation will be written by writing the symbols of the reactants and products.

That is;

Ni + Pb(NO₃)₂ → Ni(NO₃)₃ + Pb

We then balance the equation;

  • To balance the equation, we put appropriate coefficients on reactants and products, so that the number of atoms of each element is equal on both sides of the equation.
  • Thus, the balanced equation will be;

2Ni + 3Pb(NO₃)₂ → 2Ni(NO₃)₃ + 3Pb

4 0
3 years ago
How many grams of sodium hydroxide are needed to completely react with 50.0 grams of H2SO4?
Goryan [66]

Answer:

48.0 grams of NaOH I believe

3 0
2 years ago
Read 2 more answers
14. What is the pH of a 0.24 M solution of sodium propionate, NaC3H502, at 25°C? (For
Murrr4er [49]

Answer:

9.1

Explanation:

Step 1: Calculate the basic dissociation constant of propionate ion (Kb)

Sodium propionate is a strong electrolyte that dissociates according to the following equation.

NaC₃H₅O₂ ⇒ Na⁺ + C₃H₅O₂⁻

Propionate is the conjugate base of propionic acid according to the following equation.

C₃H₅O₂⁻ + H₂O ⇄ HC₃H₅O₂ + OH⁻

We can calculate Kb for propionate using the following expression.

Ka × Kb = Kw

Kb = Kw/Ka = 1.0 × 10⁻¹⁴/1.3 × 10⁻⁵ = 7.7 × 10⁻¹⁰

Step 2: Calculate the concentration of OH⁻

The concentration of the base (Cb) is 0.24 M. We can calculate [OH⁻] using the following expression.

[OH⁻] = √(Kb × Cb) = √(7.7 × 10⁻¹⁰ × 0.24) = 1.4 × 10⁻⁵ M

Step 3: Calculate the concentration of H⁺

We will use the following expression.

Kw = [H⁺] × [OH⁻]

[H⁺] = Kw/[OH⁻] = 1.0 × 10⁻¹⁴/1.4 × 10⁻⁵ = 7.1 × 10⁻¹⁰ M

Step 4: Calculate the pH of the solution

We will use the definition of pH.

pH = -log [H⁺] = -log 7.1 × 10⁻¹⁰ = 9.1

5 0
3 years ago
URGENT HELP PLEASE balance equation !20 points!
yKpoI14uk [10]
Au^2S^3+ 3H^2 = 2Au + 3H^2S
5 0
3 years ago
15. Which sample of argon gas has the same number of atoms as a 100.-milliliter sample of helium gas at 1.0 atm and 300. K? A) 5
OLga [1]

The sample of argon gas that has the same number of atoms as a 100 milliliter sample of helium gas at 1.0 atm and 300 is 100. mL at 1.0 atm and 300. K

The correct option is D.

<h3>What is the number of moles of gases in the given samples?</h3>

The number of moles of gases in each of the given samples of gas is found below using the ideal gas equation.

The ideal gas equation is: PV/RT = n

where;

  • P is pressure
  • V is volume
  • n is number of moles of gas
  • T is temperature of gas
  • R is molar gas constant = 0.082 atm.L/mol/K

Moles of gas in the given helium gas sample:

P = 1.0 atm, V = 100 mL or 0.1 L, T = 300 K

n =  1 * 0.1 / 0.082 * 300

n = 0.00406 moles

For the argon gas sample:

A. n =  1 * 0.05 / 0.082 * 300

n = 0.00203 moles

B. n =  0.5 * 0.05 / 0.082 * 300

n = 0.00102 moles

C. n =  0.5 * 0.1 / 0.082 * 300

n = 0.00203 moles

D. n =  1 * 0.1 / 0.082 * 300

n = 0.00406 moles

Learn more about ideal gas equation at: brainly.com/question/24236411

#SPJ1

8 0
1 year ago
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