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lions [1.4K]
3 years ago
11

Populations have some genetic {blank}

Chemistry
2 answers:
KengaRu [80]3 years ago
7 0

VARIATION

HOPE THIS HELPS

Juliette [100K]3 years ago
4 0
<h3>✽ - - - - - - - - - - - - - - -  ~<u>Hello There</u>!~ - - - - - - - - - - - - - - - ✽</h3>

➷ Populations have some genetic variation.

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

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8 0
3 years ago
Five kilograms of liquid carbon tetrachloride undergo a mechanically reversible, isobaric change of state at 1 bar during which
Drupady [299]

Answer:

Explanation:

From the information given:

Mass of carbon tetrachloride = 5 kg

Pressure = 1 bar

The given density for carbon tetrachloride = 1590 kg/m³

The specific heat of carbon tetrachloride =  0.84 kJ/kg K

From the composition, the initial volume of carbon tetrachloride will be:= \dfrac{5 \ kg }{1590 \ kg/m^3}

= 0.0031 m³

Suppose \beta is independent of temperature while pressure is constant;

Then:

The change in volume can be expressed as:

\int ^{V_2}_{V_1} \dfrac{dV}{V} =\int ^{T_2}_{T_1} \beta dT

In ( \dfrac{V_2}{V_1})  = \beta (T_2-T_1)

V_2 = V_1 \times exp (\beta (T_2-T_1))

V_2 = 0.0031 \ m^3  \times exp  (1.2 \times 10^{-3} \times 20)

V_2 = 0.003175 \ m^3

However; the workdone = -PdV

W = -1.01 \times 10^5 \ Pa \times ( 0.003175 m^3 - 0.0031 \ m^3)

W = - 7.6 J

The heat energy Q = Δ h

Q = mC_p(T_2-T_1)

Q = 5 kg \times 0.84 \ kJ/kg^0 C \times 20

Q = 84 kJ

The internal energy is calculated by using the 1st law of thermodynamics; which can be expressed as;

ΔU = ΔQ + W

ΔU = 84 kJ + ( -7.6 × 10⁻³ kJ)

ΔU = 83.992 kJ

3 0
3 years ago
A sample of gas occupies 40.0 mL at -123°C. What volume does the sample occupy at 27°C if the pressure is held constant? V1T2 =
Brums [2.3K]

Answer:

80mL

Explanation:

Step 1:

Data obtained from the question.

Initial Volume (V1) = 40mL

Initial temperature (T1) = –123°C

Final temperature (T2) = 27°C

Final volume (V2) =..?

Step 2:

Conversion of celsius temperature to Kelvin temperature.

T(K) = T(°C) + 273

Initial temperature (T1) = –123°C =

–123°C + 273 = 150K

Final temperature (T2) = 27°C = 27°C + 273 = 300K

Step 3:

Determination of the final volume.

This can be obtained as follow:

V1/T1 = V2/T2

Initial Volume (V1) = 40mL

Initial temperature (T1) = 150K

Final temperature (T2) = 300

Final volume (V2) =..?

V1/T1 = V2 /T2

40/150 = V2 /300

Cross multiply

150 x V2 = 40 x 300

Divide both side by 150

V2 = (40 x 300) /150

V2 = 80mL

Therefore, the new volume of the gas is 80mL

6 0
3 years ago
The state of matter of the interior of the sun and other stars​
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Explanation:

7 0
3 years ago
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What does a plant produce during the process of photosynthesis?
slavikrds [6]

Answer:

C

Explanation:

3 0
3 years ago
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