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pickupchik [31]
3 years ago
7

Two charges are placed 0.100 m apart from each other and experience a force of 100 N. Which statement about the electric force i

s correct for what happens if both charges are moved so that they are 0.500 m apart from each other?
a.The new electric force will be greater than 100 N because a decrease in the distance between charges causes an increase in the force.

b.The new electric force will be greater than 100 N because increasing the distance between charges causes an increase

c.The new electric force will be less than 100 N because an increase in the distance between charges causes a decrease in the force.

d.The new electric force will be less than 100 N because a decrease in the distance between charges causes a decrease in the force.
Physics
1 answer:
Elodia [21]3 years ago
5 0

Answer:https://www.khanacademy.org/science/high-school-physics/electric-charge-and-electric-force/coulombs-law-and-electric-force/v/coulombs-law

Explanation: Here is a link to a video that might help you

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A ball having mass 2 kg is connected by a string of length 2 m to a pivot point and held in place in a vertical position. A cons
Virty [35]

Complete Question

A ball having mass 2 kg is connected by a string of length 2 m to a pivot point and held in place in a vertical position. A constant wind force of magnitude 13.2 N blows from left to right. Pivot Pivot F F (a) (b) H m m L L If the mass is released from the vertical position, what maximum height above its initial position will it attain? Assume that the string does not break in the process. The acceleration of gravity is 9.8 m/s 2 . Answer in units of m.What will be the equilibrium height of the mass?

Answer:

H_m=1.65m

H_E=1.16307m

Explanation:

From the question we are told that

Mass of ball M=2kg

Length of string L= 2m

Wind force F=13.2N

Generally the equation for \angle \theta is mathematically given as

tan\theta=\frac{F}{mg}

\theta=tan^-^1\frac{F}{mg}

\theta=tan^-^1\frac{13.2}{2*2}

\theta=73.14\textdegree

Max angle =2*\theta= 2*73.14=>146.28\textdegree

Generally the equation for max Height H_m is mathematically given as

H_m=L(1-cos146.28)

H_m=0.9(1+0.8318)

H_m=1.65m

Generally the equation for Equilibrium Height H_E is mathematically given as

H_E=L(1-cos73.14)

H_E=0.9(1+0.2923)

H_E=1.16307m

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