Answer:
t=14ns
Explanation:
We make the relation between the specific access time and the memory percentage in each level, so


Average Access Time is 14 nsec.
Answer:
a) 229.4281 hp.
b) 262.15 ft3/min.
Explanation:
Given data:
P1 = 14.2 psi
T1 = 60°F = 520° R
P2 = 120 psi
T2 = 500°F = 960° R
volumetric flow rate ( Av1 ) = 1200 ft^3 /min = 20 ft^3 / sec
attached below is the detailed solution
Answer:
P = 80.922 KW
Explanation:
Given data;
Length of load arm is 900 mm = 0.9 m
Spring balanced read 16 N
Applied weight is 500 N
Rotational speed is 1774 rpm
we know that power is given as

T Torque = (w -s) L = (500 - 16)0.9 = 435.6 Nm
angular speed
Therefore Power is

P = 80.922 KW
Answer:
When the expenditure increased, then the consumer's expenditure is increased to Rs.150 and when the price falls of the good it becomes Rs.5. Then, Good X will be Rs.10.
last question:If the Good X falls by 20%, then, it will be Rs.2, and according to his demand 100 units will be equal to Rs.200.
cause if one unit=rs.2, then 100units=100×2=200.
Answer:
γ
=0.01, P=248 kN
Explanation:
Given Data:
displacement = 2mm ;
height = 200mm ;
l = 400mm ;
w = 100 ;
G = 620 MPa = 620 N//mm²; 1MPa = 1N//mm²
a. Average Shear Strain:
The average shear strain can be determined by dividing the total displacement of plate by height
γ
= displacement / total height
= 2/200 = 0.01
b. Force P on upper plate:
Now, as we know that force per unit area equals to stress
τ = P/A
Also, τ = Gγ
By comapring both equations, we get
P/A = Gγ
------------ eq(1)
First we need to calculate total area,
A = l*w = 400 * 100= 4*10^4mm²
By putting the values in equation 1, we get
P/40000 = 620 * 0.01
P = 248000 N or 2.48 *10^5 N or 248 kN