Answer:
use the dimensions shown in the figure
Answer: The number of gram of ammonia gas () contained in the a 3.0L vessel at 305 K with a pressure of 1.50 atm is 3.048 g.
Explanation:
Given: Volume = 3.0 L
Temperature = 305 K
Pressure = 1.50 atm
Formula used to calculate the number of moles is as follows.
PV = nRT
where,
P = pressure
V = volume
n = no. of moles
R = gas constant = 0.0821 L atm/mol K
T = temperature
Substitute the values into above formula as follows.
It is known that moles is the mass of substance divided by its molar mass.
Hence, mass of ammonia gas (molar mass = 17.03 g/mol) is as follows.
Thus, we can conclude that the number of gram of ammonia gas () contained in the a 3.0L vessel at 305 K with a pressure of 1.50 atm is 3.048 g.
Answer:
10.984mm
Explanation:
by elastic modulus
stress=modulus of elasticity*strain
stress=loading/area area" cross-section"
11mm=0.011m
area=π(d/2)^2=π(0.011/2)^2=9.503*10^-5 square meter
stress=55000/(9.503*10^-5)=578.745 MPa
convert MPa and GPa to pascal.
strain=stress/modulus=(578.745*10^6)/(125*10^9)=0.00463............axial strain
v=Poisson ratio
lateral strain=(-v)*axial strain= -0.31*0.00463
lateral strain= -1.4353*10^-3=change in diameter/ original diameter
change in diameter=(-1.4353*10^-3)*0.011= -1.57883*10^-5 m
negative indicates decrease in diameter.
decrease in dia.=0.01578mm
new diameter=11-0.01578= 10.984mm
Answer:a government website/A.Gov
Explanation:
I looked it up I also put this as my answer so i don’t know if it’s right or not
Answer: the answer for the question is a
Explanation: