Answer:
1. 0.50
2. 0.75
3. 0.65
Explanation:
1. For the bid being successful with a 50-50 chance, we have the probability:
50/(50 + 50) = 50 / 100 = 0.50
2. Given the request for additional info:
Probability = probability of request and successful / probability of successful
= 75 / 100 = 0.75
3. We will evaluate the probability of being successful given its request
We will use the Bayesian theorem
= [P(request | successful) * P(successful)] / [P(request | successful) * P(successful) + P(request | unsuccessful) * P(unsuccessful)]
= ( 0.75 * 0.5) / (0.75 * 0.5 + 0.4 * 0.5)
= 0.65
Answer:
diameter of the sprue at the bottom is 1.603 cm
Explanation:
Given data;
Flow rate, Q = 400 cm³/s
cross section of sprue: Round
Diameter of sprue at the top 
= 3.4 cm
Height of sprue, h = 20 cm = 0.2 m
acceleration due to gravity g = 9.81 m/s²
Calculate the velocity at the sprue base
= √2gh
we substitute
= √(2 × 9.81 m/s² × 0.2 m )
= 1.98091 m/s
= 198.091 cm/s
diameter of the sprue at the bottom will be;
Q = AV = (π
/4) ×
= √(4Q/π)
we substitute our values into the equation;
= √(4(400 cm³/s) / (π×198.091 cm/s))
= 1.603 cm
Therefore, diameter of the sprue at the bottom is 1.603 cm
Answer:
2.77mpa
Explanation:
compressive strength = 20 MPa. We are to find the estimated flexure strength
We calculate the estimated flexural strength R as
R = 0.62√fc
Where fc is the compressive strength and it is in Mpa
When we substitute 20 for gc
Flexure strength is
0.62x√20
= 0.62x4.472
= 2.77Mpa
The estimated flexure strength is therefore 2.77Mpa
