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jarptica [38.1K]
3 years ago
14

a train is sitting still at the top of 990-m mountain. it then coasts down the mountain and back up another mountain that is 520

m high. what is the train's speed at the top of the second hill?
Physics
1 answer:
MaRussiya [10]3 years ago
5 0

Answer:

Explanation:

At the top of 520 m high mountain , the train will lose potential energy due to loss of height from 990 m to 520 m and gain kinetic energy .

Loss of height = 990 - 520 = 470 m

Loss of potential energy = m x g x 470 where m is mass of the train .

Gain of kinetic energy = 1/2 m v² where v is velocity of train at the top of 550 m high mountain .

1/2 m v² = m x g x 470

v² = 2 x 9.8 x 470

v = 95.98 m /s

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