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julia-pushkina [17]
3 years ago
13

What is the maximum height achieved if a 0.400 kg mass is thrown straight upward with an initial speed of 40.0 m⋅s−1? Ignore the

effect of air resistance
Physics
1 answer:
AfilCa [17]3 years ago
3 0

The maximum height : 81.63 m

<h3>Further explanation</h3>

Given

0.4 kg mass

vo = initial speed = 40 m/s

Required

the maximum height

Solution

We can use the law of conservation energy(ME=PE+KE) or use parabolic motion

For parabolic motion :

h max = (vo²sin²θ)/2g

θ = 90°(straight upward)

Input the value :

h max = (40²sin²90°)/2 x 9.8

h max = 81.63 m

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Answer:

See answer

Explanation:

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A = \pi r^2

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Part A)

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after the interval \Delta t= 2.4 [m/s]

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now, the EMF is defined as:

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Alternating Current In Europe, the voltage of the alternating current coming through an electrical outlet can be modeled by the
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Answer:

\frac{50}{\pi }Hz

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Where;

V = amplitude value of the voltage

ω = angular frequency = 2 π f        [f = cyclic frequency or simply, frequency]

Ф = phase difference between voltage and current.

<u><em>Now,</em></u>

From the question,

V(t) = 230 sin (100t)              ---------------(ii)

<em><u>By comparing equations (i) and (ii) the following holds;</u></em>

V = 230

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Vector A has a magnitude of 50 units and points in the positive x direction. A second vector, B , has a magnitude of 120 units a
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A) Vector A

The x-component of a vector can be found by using the formula

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