Initial velocity: 0
final velocity: 7 m/s
a = 3.6
t = ?
x = ?
(7-0)/3.6 = t
t = 1.94 s
It would be Thermal Radiation
Car A take a time of 2.55hr and car B take a time of 2.14 hr
We know that distance divide by time is speed
here it is given that car A to reach a gas station a distance 189 km from the school traveling at a speed of 74 km/hr
so speed=distance/time
s=d/t
t=d/s
=189/74
=2.55hr
In case of car B it is given that The distance from the is 199.8km, car b is traveling at a speed of 93 km/hr
s=d/t
t=d/s
=199.8/93
=2.14hr
so from the above given data and the formula we solved and found out the time taken by car A is 2.55h and car B is 2.14h
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Answer:
Acceleration of proton will be 
Explanation:
We have given a proton is placed in an electric field of intensity of 700 N/C
So electric field E = 700 N/C
Mass of proton 
Charge on proton 
So electric force on the proton 
This force will be equal to force due to acceleration of the proton
According to newton's law force is given by F = ma
So 

So acceleration of proton will be 