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Liono4ka [1.6K]
3 years ago
7

Water travels through many different pathways within the hydrologic cycle. For example, water vapor in the atmosphere could cond

ense into clouds, fall to Earth’s surface as precipitation, and then accumulate in a pond. If a horse drinks the water in the pond, which of the following is a likely next step for that water in the hydrologic cycle?
A.
The water will be permanently trapped and reused inside the horse's body.
B.
The water will be absorbed by the horse's skin and turned into carbon dioxide.
C.
The water will evaporate from the horse's stomach into the air.
D.
The water will leave the horse when the horse sweats or urinates.
Chemistry
2 answers:
liraira [26]3 years ago
8 0

Answer:

D

Explanation:

it's probably D because that what happens with every living creature. The other options don't make sense.

Hope it helps :)

Anit [1.1K]3 years ago
5 0
It would most likely be D because that’s how most of the things would be processed but sorry if I’m wrong.
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aksik [14]

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3 0
2 years ago
The flame produced by the burner of a gas (propane) grill is a pale blue color when enough air mixes with the propane (C3H8) to
adelina 88 [10]

Answer:

At the burner temp. and pressure, 18.85 litres of air is needed to completely combust each gram of propane

Explanation:

The combustion stoichiometry is as follows:

      C₃H₈ + 5O₂  = 4 H₂O + 3CO₂      The molecular weights (g/mol) are:

MW  44    5x32      4x18    3x44

So each gram of propane is 1/44 = 0.02272 mol propane

and will need 5 x 0.02272 = 0.1136 mol oxygen

At 0.21 mol fraction oxygen in air, 0.1136 / 0.21 = 0.54 mol air is needed to burn the propane.

At the low pressure in the burner we can use the Ideal Gas Law

PV=nRT, or V = nRT/P

P = 1.1 x 101325 Pa = 111457 Pa

T = 195°C + 273 = 468 K

R = 8.314

and we calculated n = number of moles air = 0.54 mol

So V m³ = 0.54 x 8.314 x 468 / 111457 = 0.0188 m³ = 18.85 litres air.

6 0
4 years ago
Using a 300 MHz NMR instrument:
Softa [21]

Answer:

a. 750Hz, b. 4.0ppm, c. 600Hz

Explanation:

The Downfield Shift (Hz) is given by the formula

Downfield Shift (Hz) = Chemical Shift (ppm) x Spectrometer Frequency (Hz)

Using the above formula we can solve all three parts easily

a. fspec = 300 MHz, Chem. Shift = 2.5ppm, 1MHz = 10⁶ Hz, 1ppm (parts per million) = 10⁻⁶

Downfield Shift (Hz) = 2.5ppm x 300MHz x (1Hz/10⁶MHz) x (10⁻⁶/1ppm)

Downfield Shift = 750 Hz

The signal is at 750Hz Downfield from TMS

b. Downfield Shift = 1200 Hz, Chemical Shift = ?

Chemical Shift = Downfield shift/Spectrometer Frequency

Chemical Shift = (1200Hz/300MHz) x (1ppm/10⁻⁶) = 4.0 ppm

The signal comes at 4.0 ppm

c. Separation of 2ppm, Downfield Shift = ?

Downfield Shift (Hz) = 2(ppm) x 300 (MHz) x (1Hz/10⁶MHz) x (10⁻⁶/1ppm) = 600 Hz

The two peaks are separated by 600Hz

6 0
3 years ago
7 grams of oxygen gas is reacted with excess C4H8. How many grams of CO2 gas at STP are produced?
ladessa [460]
I think 14 are produced because if you go up by that you get it
4 0
3 years ago
Write the IUPAC names for the following compounds.
atroni [7]
Benzine
Bromine
Clorine
5 0
2 years ago
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