6A. Which pair of charges has a stronger attraction, top or bottom?

A rocket starts from rest and moves upward from the surface of the earth. For the first 10s of its motion, the vertical accelera

Naily [24]

Since the rocket’s acceleration is 3.00 m/s^3 * t, its acceleration is increasing at the rate of 3 m/s^3 each second. The equation for its velocity at a specific time is the integral of the acceleration equation.

vf = vi + 1.5 * t^2, vi = 0 
vf = 1.5 * 10^2 = 150 m/s 
This is the rocket’s velocity at 10 seconds. The equation for its height at specific time is the integral velocity equation

yf = yi + 0.5 * t^3, yi = 0 
yf = 0.5 * 10^3 = 500 meters 
This is the rocket’s height at 10 seconds. 

Part B 
What is the speed of the rocket when it is 345 m above the surface of the earth? 
Express your answer with the appropriate units. 

Use the equation above to determine the time. 

345 = 0.5 * t^3 
t^3 = 690 
t = 690^⅓ 
This is approximately 8.837 seconds. Use the following equation to determine the velocity at this time. 

v = 1.5 * t^2 = 1.5 * (690^⅓)^2 
This is approximately 117 m/s. 

The graph of height versus time is the graph of a cubic function. The graph of velocity is a parabola. The graph of acceleration versus time is line. The slope of the line is the coefficient of t. This is a very different type of problem. For the acceleration to increase, the force must be increasing. To see what this feels like slowly push the accelerator pedal of a car to the floor. Just don’t do this so long that your car is speeding!!

3 0

4 years ago

Read 2 more answers

what does 1N equal? It happens to be one of the questions on my "Newton's Laws of Motion Exercises" paper.

san4es73 [151]

1 Newton is equal to the amount of force required to accelerate an object at a rate of 1 metre per second, every second. One newton is the force needed to accelerate one kilogram of mass at the rate of one metre per second squared in direction of the applied force.

8 0

4 years ago

A 0.9 kg ball attached to a cord is whirled in a vertical circle of radius 2.5 m. Find the minimum speed needed at the top of th

lapo4ka [179]

Answer:

The minimum speed needed at the top of the circle so that the cord remains tensioned and the ball's path remains circular is approximately is 9.903 meters per second.

Explanation:

By the Principle of Energy Conservation we understand that the minimum speed needed by the ball is that speed such that maximum height reached is equal to the diameter of the vertical circle, that is:

$K =U_{g}$ (1)

Where:

$K$ - Translational kinetic energy, measured in joules.

$U_{g}$ - Gravitational potential energy, measured in joules.

By definitions of translational kinetic and gravitational potential energies, we expand the equation above and clear the initial speed of the ball:

$\frac{1}{2}\cdot m \cdot v^{2} = m\cdot g\cdot h$

$v = \sqrt{2\cdot g\cdot h}$ (2)

Where:

$m$ - Mass, measured in kilograms.

$v$ - Initial speed, measured in meters per second.

$g$ - Gravitational acceleration, measured in meters per square second.

$h$ - Maximum height of the ball, measured in meters.

If we know that $g = 9.807\,\frac{m}{s^{2}}$ and $h = 5\,m$ , then the initial speed of the ball is:

$v = \sqrt{2\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (5\,m)}$

$v\approx 9.903\,\frac{m}{s}$

The minimum speed needed at the top of the circle so that the cord remains tensioned and the ball's path remains circular is approximately is 9.903 meters per second.

3 0

4 years ago

3. A 6 kg block moving to the right at 4 m/s collides with and sticks to a stationary block of unknown mass. If the two blocks m

Sphinxa [80]

Answer: 2kg

Explanation:

This problem is a textbook conservation of momentum problem. The intial momentum is equal to the final momentum. For the initial state of each block, only the first one was moving. Then they both combine to move together.

Pi = Pf

with p = mv

(6kg)*(4m/s) = (6kg+xkg)(3m/s)

Let x equal the unknown mass of block 2

24 = 18 + 3x

6 = 3x

x = 2kg

6 0

3 years ago

Looking straight downward into a rain puddle whose surface is covered with a thin ﬁlm of gasoline. you notice a swirlingpattern

Helen [10]

Answer:

Explanation:

In case of colored film we apply the theory of interference.

Condition that colored fringe is formed ( constructive interference)

2μt = λ/ 2 ( minimum order)

t = λ/ 4μ

= 540 / 4 x 1.38

= 97.83 nm

4 0

3 years ago