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Sergio039 [100]
3 years ago
12

What was Galileo’s contribution to the study of motion?

Physics
2 answers:
babunello [35]3 years ago
8 0

Before giving you the answer straight away, I’d like to make sure you understand each option.


FIRST OPTION


“He developed the three laws of motion."


This option is not only the incorrect answer, but it is an incorrect statement. Galileo did not develop the three laws of motion. Isaac Newton was the one to compiled the three laws of motion.


SECOND OPTION


“He was the first to systematically study force and motion."


This option is a statement is true, and it could also be the correct answer. Galileo Galilei used experiments to search for the cause of motion.


THIRD OPTION


“He was the first to discover gravity."


This option is not only the incorrect answer, but it is an incorrect statement. Galileo was not the person to discover gravity. Sir Isaac Newton was the first to discover gravity.


FINAL OPTION


“He improved on Newton's laws."


This option is not only the incorrect answer, but it is an incorrect statement. Galilei did not improve Sir Isaac Newton’s laws.


Now that we’ve gone through each of the options individually, we can go ahead and determine the correct answer to the question, which is...


B ) He was the first to systematically study force and motion.



- Marlon Nunez

Marta_Voda [28]3 years ago
8 0

Answer: Option B

Explanation: Galileo Galilei (1564 - 1642) was an Italian physicist, mathematician, engineer, and philosopher that is mainly known for the telescope and the heliocentrism.

One of the first things Galileo contributed to science was on forces and motion. Because of his mathematic formation, he had a very systematic and logic approach to the science and laws of nature, so his studies where advanced for the time.

The right answer here would be option B: "He was the first to systematically study force and motion."

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The diagram below shows different weights on the see-saw. Will the see-saw move?
oee [108]

Answer:

yes it will

Explanation:

8 0
3 years ago
A .5 kg toy train car moving forward at 3 m/s collides with and sticks to a .8 kg toy car that is traveling at 2 m/s what is the
Viktor [21]
Here we have perfectly inelastic collision. Perfectly inelastic collision is type of collision during which two objects collide, stay connected and momentum is conserved. Formula used for conservation of momentum is:
m_{1} * v_{1} + m_{2} * v_{2} = m_{1} * v'_{1}+ m_{2} * v'_{2}

In case of perfectly inelastic collision v'1 and v'2 are same.

We are given information:
m₁=0.5kg
m₂=0.8kg
v₁=3m/s
v₂=2m/s
v'₁=v'₂=x

0.5*3 + 0.8*2 = 0.5*x + 0.8*x
1.5 + 1.6 = 1.3x
3.1 = 1.3x
x = 2.4 m/s
4 0
3 years ago
How do you find input energy with only the efficiency and output energy given?
iris [78.8K]

Answer:

power output/transformer efficiency multiply by 100%

Explanation:

derrive the formula from efficiency=power output/power input multiply by 100%

8 0
4 years ago
Air pressure may be represented as a function of height above the surface of the Earth as shown below.. P(h) = P_0 e^-.00012h. .
Rufina [12.5K]

Answer. Second Option: .85p_o=p_o e^-.00012h


Solution:

P(h)=Po e^(-0.00012h)

Air pressure: P(h)

Height above the surface of the Earth (in meters): h

Air pressure at the sea level: Po

Height at which air pressure is 85% of the air pressure at sea level:

h=?, P(h)=85% Po

P(h)=(85/100) Po

P(h)=0.85 Po

Replacing P(h) by 0.85 Po in the formula above:

P(h)=Po e^(-0.00012h)

0.85 Po = Po e^(-0.00012h)

5 0
3 years ago
Read 2 more answers
Suppose that a rectangular toroid has 1,500 windings and a self-inductance of 0.060 H. If the height of the rectangular toroid i
V125BC [204]

Answer:

Current in the toroid will be I=17.32\times 10^{-3}A

Explanation:

We have given number of winding in rectangular toroid N = 1500

Self inductance of toroid L = 0.06 H

Magnetic energy stored in toroid E=9\times 10^{-16}J

We have to find the current in the toroid

Magnetic energy stored is equal to E=\frac{1}{2}Li^2

9\times 10^{-6}=\frac{1}{2}\times 0.06\times I^2

I=17.32\times 10^{-3}A

So current in the toroid will be I=17.32\times 10^{-3}A

5 0
4 years ago
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