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Reptile [31]
3 years ago
15

What is the oxidation state of nitrogen in a nh4f molecule

Chemistry
1 answer:
joja [24]3 years ago
8 0

Answer:

+3

Explanation:

NH₄F

=> N + 4H + F = 0

=> N + 4(+1) + 1(-7) = 0

=> N = 7 - 4 = +3

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If one of the reactants in a reaction is Na2O, what is known about the products?
const2013 [10]

D. The products will have at least 2 Na atoms and 1 O atom.

<h3>Further explanation</h3>

If we refer to the law of mass conservation, which states that

<em>In a closed system, the masses before and after the reaction are the same </em>

then the number of atoms in the reactance will be the same as the number of atoms in the product

In this problem it is known that Na₂O is one of the reactants so that the product of Na atoms and O atoms will at least equal the number of atoms in the bond, namely 2 Na and 1 O

Like an example of this Na₂O reaction:

Na₂O + H₂O ⇒ 2 NaOH

Na : left =2, right = 2

O : left=2, right = 2

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3 years ago
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A mixture contains only NaCl and Al2(SO4)3. A 1.45-g sample of the mixture is dissolved in water, and an ex- cess of NaOH is add
chubhunter [2.5K]

Answer:

The mass percent of aluminum sulfate in the sample is 16.18%.

Explanation:

Mass of the sample = 1.45 g

Al_2SO_3+6NaOH\rightarrow 2Al(OH)_3+3Na_2SO_4

Mass of the precipitate = 0.107 g

Moles of aluminum hydroxide = \frac{0.107 g}{78 g/mol}=0.001372 mol

According to reaction, 2 moles of aluminum hydroxide is obtained from 1 mole of aluminum sulfate .

Then 0.001372 moles of aluminum hydroxide will be obtained from:

\frac{1}{2}\times 0.001372 mol=0.000686 mol

Mass of 0.000686 moles of aluminum sulfate :

= 0.000686 mol × 342 g/mol = 0.2346 g

The mass percent of aluminum sulfate in the sample:

=\frac{ 0.2346 g}{1.45g}\times 100=16.18\%

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Answer:

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Explanation:

It makes sense

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Nonmetals are ___.
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