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3 years ago

A car ends up colliding with a tree. Compare the force the car exerts on the tree with the force the tree exerts on the car.

1 answer:

4 0

Answer: The force will exert into the tree causing it to absorb the compact hit by the car which means the car gets damaged severely but the tree maybe only has a tiny crack. Mark me as Brainliest! :)

Explanation:

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A dockworker loading crates on a ship finds that a 21-kg crate, initially at rest on a horizontal surface, requires a 73-N horiz

Nataliya [291]

1) Static friction coefficient: 0.355

The crate is initially at rest. The crate remains at rest until the horizontal pushing force is less than the maximum static frictional force.

The maximum static frictional force is given by

$F_s = \mu_s mg$

where

$\mu_s$ is the static coefficient of friction

m = 21 kg is the mass of the crate

g = 9.8 m/s^2 is the acceleration due to gravity

The horizontal force required to set the crate in motion is 73 N: this means that this is the value of the maximum static frictional force. So we have

$F_s=73 N$

Using this information into the previous equation, we can find the coefficient of static friction:

$\mu_s = \frac{F}{mg}=\frac{73 N}{(21 kg)(9.8 m/s^2)}=0.355$

2) Kinetic friction coefficient: 0.267

Now the crate is in motion: this means that the kinetic friction is acting on the crate, and its magnitude is

$F_k = \mu_k mg$ (1)

where

$\mu_k$ is the coefficient of kinetic friction

There is a horizontal force of

F = 55 N

pushing the crate. Moreover, the speed of the crate is constant: this means that the acceleration is zero, a = 0.

So we can write Newton's second law as

$F-F_k = ma = 0$

And by substituting (1), we can find the value of the coefficient of kinetic friction:

$F-\mu_k mg = 0\\\mu_k = \frac{F}{mg}=\frac{55 N}{(21 kg)(9.8 m/s^2)}=0.267$

5 0

3 years ago

You are determining the mass of an object using a triple beam balance. When the pointer is lined up with the zero mark, the ride

astra-53 [7]

We add the values on each of the riders:
300 + 20 + 8
= 328 grams

3 0

4 years ago

Read 2 more answers

Consider a step-down transformer with 15 turns in the primary and 6 turns in the secondary windings. Calculate the input impedan

AURORKA [14]

Answer:

Input impedance of this transformer is 50 ohms.

Explanation:

Given that,

Number of turns in the primary coil, $N_p=15$

Number of turns in the secondary coil, $N_s=6$

Output impedance of the transformer, $V_o=8\ \Omega$

The number of turns and the impedance ratio in the step down transformer is given by :

$\dfrac{15}{6}=\sqrt{\dfrac{Z_p}{Z_s}}\\\\\dfrac{15}{6}=\sqrt{\dfrac{Z_p}{8}}\\\\Z_p=50\ \Omega$

So, the input impedance of this transformer is 50 ohms. Hence, this is the required solution.

8 0

3 years ago

Global expansion offers companies the opportunity to generate greater profits than companies that focus strictly on _____.

Kryger [21]

Answer:

The domestic market

____________________________________________________

Global expansion does, in fact offer companies the opportunity to generate greater profits than companies that focus strictly on the domestic market.

____________________________________________________

Hope this helps!

6 0

3 years ago

A(n) a0 is software that contains rows and columns used to make calculations, organize information, and make comparisons.

Scilla [17]

The appropriate response is spreadsheets. It is a sheet of paper that shows bookkeeping or other information in columns and rows; a spreadsheet is likewise a computer application program that reenacts a physical spreadsheet by catching, showing, and controlling information masterminded in lines and sections.

7 0

3 years ago