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3 years ago

A car ends up colliding with a tree. Compare the force the car exerts on the tree with the force the tree exerts on the car.

1 answer:

4 0

Answer: The force will exert into the tree causing it to absorb the compact hit by the car which means the car gets damaged severely but the tree maybe only has a tiny crack. Mark me as Brainliest! :)

Explanation:

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[C]utting programs that were not effective or essential and even some that were, but are now unaffordable; and precisely targeti

zalisa [80]

Option B i.e discretion is the right and correct answer.

[C]utting programs that were not effective or essential and even some that were, but are now unaffordable; and precisely targeting our investments. Every department will feel the impact of these reductions as they cut programs or tighten their belts to free up more resources for areas critical to economic growth. —President Barack Obama, 2012 Budget Message of the President.

The President above clearly refers to the Discretion Spending where portion of the budget is decided by Congress through the annual appropriations.

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3 years ago

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The double inclined plane supports two blocks A and B, each having a weight of 10 lb. If the coefficient of kinetic friction bet

Vladimir79 [104]

Answer:

Explanation:

Left block is on surface with higher inclination so it will go down . If T be tension

For motion of block A ,

net force = mgsin60 - (T + mg cos 60 x μ ) , μ is coefficient of friction .

ma = mgsin60 - T - mg cos 60 x .1

10a = 277.13 - T - 16

= 261.13 - T

T = 261.13 - 10a

For motion of block B

T - mg sin30 - mgcos30 x μ = ma

T- 160 - 27.71 = 10 a

261.13 - 10a - 160 - 27.71 = 10a

73.42 = 20a

a = 3.67 ft / s²

common acceleration = 3.67 ft / s²

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4 years ago

Which of the options below has the correct number of each element for the compound?

slamgirl [31]

Answer:

there are no options buddy

7 0

3 years ago

Read 2 more answers

What is the electrical charge of a neutral atom that has lost on electron?

dybincka [34]

I believe it is positive.

6 0

4 years ago

que 2. Why do we keep frequency constant instead of keeping vibrating length constam second law of vibrating string?

ella [17]

Answer:

The second law of a vibrating string states that for a transverse vibration in a stretched string, the frequency is directly proportional to the square root of the string's tension, when the vibrating string's mass per unit length and the vibrating length are kept constant

The law can be expressed mathematically as follows;

$f = \dfrac{1}{2\cdot l} \cdot \sqrt{\dfrac{T}{m} }$

The second law of the vibrating string can be verified directly, however, the third law of the vibrating string states that frequency is inversely proportional to the square root of the mass per unit length cannot be directly verified due to the lack of continuous variation in both the frequency, 'f', and the mass, 'm', simultaneously

Therefore, the law is verified indirectly, by rearranging the above equation as follows;

$m = \dfrac{1}{ l^2} \cdot \dfrac{T}{4\cdot f^2} }$

From which it can be shown that the following relation holds with the limits of error in the experiment

m₁·l₁² = m₂·l₂² = m₃·l₃² = m₄·l₄² = m₅·l₅²

Explanation:

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3 years ago