All categories

3 years ago

What r photons? ........................,........,..........

Physics

2 answers:

expeople1 [14]3 years ago

8 0

Answer:

The quantum of light and other electromagnetic energy, regarded as a discrete particle having zero rest mass, no electric charge, and an indefinitely long lifetime. It is a gauge boson.

AVprozaik [17]3 years ago

6 0

Answer:

in physics, a photon is a bundle of electromagnetic energy. It is the basic unit that makes up all light

Explanation:

You might be interested in

In the year 2055, a rocket was launched from a research laboratory on Mars. Mars has essentially no atmosphere. The test rocket

algol [13]

Answer:

h = 618.64 m

Explanation:

First we need to calculate the height gained by rocket while the fuel is burning. We use 2nd equation of motion for that purpose:

h₁ = Vit + (1/2)at²

where,

h₁ = height gained during the burning of fuel

Vi = Initial Velocity = 0 m/s

t = time = 7 s

a = acceleration = 8 m/s²

Therefore,

h₁ = (0 m/s)(7 s) + (1/2)(8 m/s²)(7 s)²

h₁ = 196 m

Now we use 1st equation of motion to find final speed Vf:

Vf = Vi + at

Vf = 0 m/s + (8 m/s²)(7 s)

Vf = 56 m/s

Now, we calculate height covered in free fall motion. Using 3rd equation of motion:

2ah₂ = Vf² - Vi²

where,

a = - 3.71 m/s²

h₂ = height gained during free fall motion = ?

Vf = Final Velocity = 0 m/s (since, rocket will stop at highest point)

Vi = 56 m/s

Therefore,

(2)(-3.71 m/s²)h₂ = (0 m/s)² - (56 m/s)²

h₂ = 422.64 m

So the total height gained will be:

h = h₁ + h₂

h = 196 m + 422.64 m

4 0

3 years ago

A rock is dropped from the top of a 500m cliff. How long does it take the rock to reach the bottom

Korvikt [17]

5 seconds.............

5 0

3 years ago

Why do electromagnetic waves not require a medium for travel?

FinnZ [79.3K]

Answer:

Because they propagate due to presence of magnetic and electric field.

Explanation:

An Electromagnetic wave is a transversal wave conformed of an electric field perpendicular to a magnetic field.

Maxwell established that an electric field can generate a magnetic field and vice versa, which allows the propagation of the electromagnetic wave without a medium.

8 0

3 years ago

A very strong, but inept, shot putter puts the shot straight up vertically with an initial velocity of 12.0 m/s. how long does h

Lunna [17]

The shot has a constant downward acceleration of $a_y=-9.81\,\dfrac{\mathrm m}{\mathrm s^2}$ . Since acceleration is constant, the velocity of the ball is given by

$a_y=\dfrac{v_y-v_{0y}}t$

where $v_y$ is the shot's vertical velocity at time $t$ and $v_{0y}$ is its initial vertical velocity. We're given that $v_{0y}=12.0\,\dfrac{\mathrm m}{\mathrm s}$ . So

$-9.81\,\dfrac{\mathrm m}{\mathrm s^2}=\dfrac{v_y-12.0\,\frac{\mathrm m}{\mathrm s}}t\implies v_y=12.0\,\dfrac{\mathrm m}{\mathrm s}+\left(-9.81\,\dfrac{\mathrm m}{\mathrm s^2}\right)t$

gives the shot's velocity at time $t$ .

Because acceleration is constant, we also know that

$\bar v_y=\dfrac{d_y-d_{0y}}t=\dfrac{v_y+v_{0y}}2$

where $\bar v_y$ is the average vertical velocity, $d_y$ is the vertical displacement at time $t$ , and $d_{0y}$ is the initial displacement at $t=0$ . We're given an initial displacement of $d_{0y}=2.10\,\mathrm m$ , so the displacement of the shot is

$d_y=d_{0y}+\dfrac12(v_y+v_{0y})t=d_{0y}+v_{0y}t+\dfrac12a_yt^2$

$\implies d_y=2.10\,\mathrm m+\left(12.0\,\dfrac{\mathrm m}{\mathrm s}\right)t+\dfrac12\left(-9.81\,\dfrac{\mathrm m}{\mathrm s^2}\right)t^2$

The shotputter is 1.90 m tall, a difference of 0.20 m from the initial height of the throw. So we want to find the time for the ball to reach a displacment of -0.20 m:

$-0.20\,\mathrm m=2.10\,\mathrm m+\left(12.0\,\dfrac{\mathrm m}{\mathrm s}\right)t+\dfrac12\left(-9.81\,\dfrac{\mathrm m}{\mathrm s^2}\right)t^2$