A B and C are all chemical changes. paper tearing is not.
Answer:
the powerhouse of the cell
Explanation:
jk its called adenosine triphosphate
<span>Answer
is: mass of burned butane is 11.6 g.</span>
Chemical reaction: 2C₄H₁₀ + 13O₂ → 8CO₂ + 10H₂O.
m(butane)
= 50,0 g.
<span>
V(CO</span>₂) = 17,9 L.<span>
n(CO</span>₂) = V(CO₂) ÷
Vm.<span>
n(CO</span>₂) = 17,9 L ÷ 22,4 L/mol.<span>
n(CO</span>₂) = 0,8 mol.<span>
From chemical reaction n(CO</span>₂) :
n(C₄H₁₀) = 8 : 2.<span>
n(C</span>₄H₁₀) =
0,8 mol ÷ 4.<span>
n(C</span>₄H₁₀) =
0,2 mol.<span>
m(C</span>₄H₁₀) =
n(C₄H₁₀) · M(C₄H₁₀).<span>
m(C</span>₄H₁₀) =
0,2 mol · 58 g/mol.<span>
m(C</span>₄H₁₀) =
11,6 g.
Answer:
Inhibition and tolerance.
Explanation:
Competitive inhibitors are characterized by being chemicals that are similar to the normal substrate. While non-competitive inhibitors are chemicals that bind to the enzyme and alter its shape. This renders the active site of the enzyme ineffective against the substrate. Tolerance makes a society that is fair and equitable.
Answer:
Statements 1 and 2 are correct.
Explanation:
The microenvironment around a amino acid residue can impact its pKa value according with the Born effect. If there is a positively charged environment, like in the second option, the pKa value will decrease, just as it happens in the histidine residue. So the correct answers are 1 and 2.
