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frosja888 [35]
3 years ago
6

In me franklins algebra course, eight students recently took a test their grades were as followed: 35, 77, 80, 86, 87, 90, 94, 1

00
calculate the mean and median of this data set
Mathematics
2 answers:
adell [148]3 years ago
8 0

Answer:

Mean= sum/no.

= 35+77+80+86+87+90+94+100 / 8

= 649/8

=81.125 was the mean

Median: the middle number

35, 77, 80, 86, 87, 90, 94, 100

Both are in the middle so: 86+87/2

=173/2

=86.5 as the median

AysviL [449]3 years ago
3 0

Step-by-step explanation:

followed: 35, 77, 80, 86, 87, 90, 94, 100

calculate the mean and median of this data set

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Step-by-step explanation:

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4 years ago
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Find the squares of (x+3)<br>​
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Answer:

{x}^{2}  + 6x + 9 \\

Step-by-step explanation:

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3 years ago
If x = -3, what is the value of (1 - x)^3? Explain why
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5 0
4 years ago
Find the median, first quartile, third quartile, interquartile range, and any outliers for each set of data. 111, 68, 93, 88, 74
lilavasa [31]

Answer:

Q1 = 87 ;

Q2 = 102 ;

Q3 = 115 ;

IQR = 28

OUTLIER = None

Step-by-step explanation:

Given the data:

111, 68, 93, 88, 74, 152, 119, 87, 88, 105, 84, 102, 151, 115, 112

Ordered data : 68, 74, 84, 87, 88, 88, 93, 102, 105, 111, 112, 115, 119, 151, 152

Sample size, n = 15

The first quartile, Q1 = 1/4(n+1)th term

Q1 = 1/4(15+1)th term

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The Median , Q2 = 1/2(n+1)th term

Q2 = 1/2(15+1)th term

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The third quartile, Q3 = 3/4(n+1)th term

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4 0
3 years ago
Besties can any of you help me on this because i do not know how to solve this
s344n2d4d5 [400]
The answer is D hope this helps
8 0
3 years ago
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