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Arisa [49]
3 years ago
6

A car is traveling at a speed of 65 mi/h. How long does it take to cover a distance of 235 m?

Chemistry
1 answer:
fgiga [73]3 years ago
5 0

Answer:

It will take 8.09 seconds to cover 235 meters by car with speed of 65 mile/h.

Explanation:

Speed of the car = 65 mile/h = 65  1609.34 m/h = 104,607.1 m/h

1 mile = 1609.34 m

Distance covered by the car in t time = 235 m = mile

Speed-\frac{Distance}{Time}

104,607.1 m/h=\frac{\frac{235}{1609.34} mile}{t}

t=\frac{235 m}{104,607.1 m/h}

t = 0.002246 h

1 hour = 3600 seconds

0.002246 h = 0.002246 h × 3600 seconds = 8.09 seconds

It will take 8.09 seconds to cover 235 meters by car with speed of 65 mile/h.

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A box of cleaning supplies weighs 15 N. If the box is lifted a distance of 0.60 m, how much work is done?
Nady [450]
Work Done = force x displacement. So in this case the 15N is the force (because weight is a force) and 0.60m is the displacement. Therefore 15 x 0.6 = 9 Joules of work done (btw, work done can also be referred to as energy transferred)
3 0
3 years ago
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For a particular reaction, ΔH∘=20.1 kJ/mol and Δ????∘=45.9 J/(mol⋅K). Assuming these values change very little with temperature,
tia_tia [17]

Answer:

The temperature should be higher than 437.9 Kelvin (or 164.75 °C) to be spontaneous

Explanation:

<u>Step 1:</u> Data given

ΔH∘=20.1 kJ/mol

ΔS is 45.9 J/K

<u>Step 2:</u> When is the reaction spontaneous

Consider temperature and pressure = constant.

The conditions for spontaneous reactions are:

ΔH <0

ΔS  > 0

ΔG <0  The reaction is spontaneous at all temperatures

ΔH <0

ΔS  <0

ΔG <0 The reaction is spontaneous at low temperatures ( ΔH - T*ΔS <0)

ΔH >0

ΔS  >0

ΔG <0 The reaction is spontaneous at high temperatures ( ΔH - T*ΔS <0)

<u>Step 3:</u> Calculate the temperature

ΔG <0 = ΔH - T*ΔS

T*ΔS > ΔH

T > ΔH/ΔS

In this situation:

T > (20100 J)/(45.9 J/K)

T > 437.9 K

T > 164.75 °C

The temperature should be higher than 437.9 Kelvin (or 164.75 °C) to be spontaneous

7 0
3 years ago
Consider the reaction mg(oh)2(s)→mgo(s)+h2o(l) with enthalpy of reaction δhrxn∘=37.5kj/mol what is the enthalpy of formation of
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Answer is: -601,2 kJ/mol
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</span>ΔHf(H₂O) = <span>−285,8 kJ/mol.
</span>ΔHrxn -enthalpy of reaction.
ΔHf - enthalpy of formation.
<span>ΔHrxn=∑productsΔHf−∑reactantsΔHf. 
</span>ΔHf(MgO) = -924,5 kJ/mol - (-285,8 kJ/mol) + 37,5 kj/mol.
ΔHf(MgO) = -601,2 kJ/mol.
7 0
3 years ago
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Taylor has a mass or 500 grams
aliya0001 [1]

Answer:

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8 0
2 years ago
A metal is found that has a mass of 27g and will displace 6mL of water. Calculate its density and identify the metal.
melisa1 [442]

The density of metal = 4.5 g/ml, and the metal = Titanium

<h3>Further explanation  </h3>

Density is a quantity derived from the mass and volume  

Density is the ratio of mass per unit volume  

Density formula:  

\large {\boxed {\bold {\rho ~ = ~ \frac {m} {V}}}}

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m = mass  

v = volume  

mass of metal=27 g

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The density :

\tt \rho=\dfrac{27}{6}\\\\\rho=4.5~g/ml

The metal with a density of 4.5 g/ml is Titanium

3 0
2 years ago
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