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coldgirl [10]
3 years ago
13

a student that just received their driver's license decides to buy a new car. he remembers from physics class that heat engines

have thermal efficiency that can be calculated. he asks the car dealer for a car that has a high thermal efficiency rating. the car dealer say he has a car that is 100% efficient. which law of thermodynamics best describes why the car cannot be 100% efficient?
Physics
1 answer:
blsea [12.9K]3 years ago
5 0

Answer: the first law of thermodynamics

Explanation:

You might be interested in
R S ( M ) = 2 G M c 2 , where G is the gravitational constant and c is the speed of light. It is okay if you do not follow the d
padilas [110]

The provided question's answer is "Schwarzschild radius".

The conversion factor between mass and energy is the speed of light squared.

GM/r stands for gravitational potential energy, also known as energy per unit mass.

GM/rc² then has "mass per unit mass" units. In other words, as mass/mass splits out in a dimensional analysis, "dimensionless per unit."

The derivation yields a formula for time or space coordinate ratios requiring sqrt(1 - 2GM/rc²). This number becomes 0 when r=2GM/c2, or the formula becomes infinite if in the denominator. However, there is no justification for using c² as a conversion factor there. Consider the initial expression sqrt(1 - 2GM/rc²).

Assume that m is used as the test particle's mass instead of 1. Then you have sqrt(m - 2GMm/rc² and mass units. This expression denotes that the rest energy of the test mass m you introduced into the gravitational field is "gone" at that radius.

The 2 would be absent if the gravitational field were Newtonian. However, at the event horizon, Einstein gravity is slightly stronger than Newton gravity, resulting in the factor 2 in qualitative terms.

So, the given equation is of Schwarzschild radius.

Learn more about Schwarzschild radius here:

brainly.com/question/12647190

#SPJ10

3 0
2 years ago
5.3 two 30 kg children in a 20 kg cart are stationary at the top of a hill. They start rolling down the 80 m tall hill and they
Makovka662 [10]

Answer:

<em>60008.4 J</em>

<em></em>

Explanation:

The mass of each kid = 30 kg

mass of the cart = 20 kg

The speed of the cart down the hill = 30 km/hr = 30 x 1000/3600 = 8.33 m/s

The height of the hill = 80 m

The potential energy of the boys at the top of the hill = mgh

where

m is the total mass of the kids and the cart = (30 x 2) + 20 = 80 kg

g is the acceleration due to gravity = 9.81 m/s^2

h is their height above the ground = 80 m (on the top of the hill)

substituting, we have

potential energy PE = 80 x 9.81 x 80 = 62784 J

At an instance at the bottom of the hill

their kinetic energy = \frac{1}{2} mv^2

where

v is their velocity = 8.33 m/s

m is their total mass = 80 kg

substituting, we have

kinetic energy KE = \frac{1}{2}*80*8.33^2 = 2775.6 J

Total work done on the cart is equal to the energy lost by the cart when it reached the bottom of the hill

work done by friction = PE - KE = 62784 - 2775.6 = <em>60008.4 J</em>

5 0
3 years ago
The electron gun in a television tube is used to accelerate electrons with mass 9.109 × 10−31 kg from rest to 3 × 107 m/s within
zaharov [31]

Answer:

Electric field, E = 40608.75 N/C

Explanation:

It is given that,

Mass of electrons, m=9.1\times 10^{-31}\ kg

Initial speed of electron, u = 0

Final speed of electrons, v=3\times 10^7\ m/s

Distance traveled, s = 6.3 cm = 0.063 m

Firstly, we will find the acceleration of the electron using third equation of motion as :

a=\dfrac{v^2-u^2}{2s}

a=\dfrac{(3\times 10^7)^2}{2\times 0.063}

a=7.14\times 10^{15}\ m/s^2

Now we will find the electric field required in the tube as :

ma=qE

E=\dfrac{ma}{q}

E=\dfrac{9.1\times 10^{-31}\times 7.14\times 10^{15}}{1.6\times 10^{-19}}

E = 40608.75 N/C

So, the electric field required in the tube is 40608.75 N/C. Hence, this is the required solution.

3 0
3 years ago
A wire with a circular cross section has radius 0.16 mm and is lying along the x axis from x=0 to x=0.20 m. The wire is made of
kipiarov [429]

Answer:

Resistance = 68.23 Ω

Explanation:

Let's start off by remembering the fact that when resistors are connected in series, their resistances is added up to find the total resistance.

The equation for resistance using resistivity is given below:

Resistance = Resistivity * Length / Area

where Length = x

Resistivity = 3x^5

and Area = \pi *0.00016^2 = 8.04 * 10^(-8)   meter squared

Substituting in the value of resistivity, length and area we get:

Resistance = \frac{ (3x^5) * (x) }{(8.04*10^-^8)}

Resistance = \frac{ (3x^6) }{(8.04*10^-^8)}

Since resistance in series is added, we can simply integrate this formula over the length (x = 0 to x = 0.2) to get the total resistance.

Resistance = \int\ {\frac{ (3x^6) }{(8.04*10^-^8)}} \, dx

Resistance = (5.4857*10^-^6) /(8.04*10^-^8)

Resistance = 68.23 Ω

3 0
3 years ago
Read 2 more answers
A string has a mass of 0.8Kg. The length of the string is 2m. The tension in the string is 5N. The string is stretched and fixed
viktelen [127]

Answer:

1.25Hz

Explanation:

For waves on a string, the second harmonic is obtained from;

2fo = 1/l √T/M

Where;

l = length of the string

M= mass in kilograms

T = tension in the string

2fo = 1/2√5/0.8

2f0 = 1.25Hz

3 0
2 years ago
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