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Andrew [12]
3 years ago
9

Find the common ratio.

Mathematics
2 answers:
statuscvo [17]3 years ago
7 0

Answer:

324, -972, 2916

Step-by-step explanation:

Divide a number by the previous number to find r.

r = -12/4 = -3

Multiply a number by r to find the next number.

-108 * (-3) = 324

324 * (-3) = -972

-972 * (-3) = 2916

Answer: 324, -972, 2916

zheka24 [161]3 years ago
4 0

Answer:

1.  (1 : -3) is the common ratio

2.   324, 972, 2916

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anastassius [24]
Opposite Numbers and their Sums:

1+6=7
2+7=9
3+8=11
4+9=13
5+10=15

Because of this, the pair of opposite numbers are 3 and 8 if you want the pair that equal 11.
7 0
2 years ago
How to prove that a shape is a square on the coordinate plane?
Goshia [24]
If a quadrilateral has four congruent sides and four right angles, then it's a square, and also If two consecutive sides of a rectangle are congruent, then it's a square.

Glad I could help, Have a great day!
5 0
3 years ago
Read 2 more answers
Please help me out!​
IgorLugansk [536]

w=7.5

Step-by-step explanation:

area of triangle is 6x5=30/2= 15 and then you divide 15 which 7.5

8 0
2 years ago
In her metalwork class, Anja cut a square of
Paul [167]

Given:

Anju cut square of tin, of edge 3.7 cm, from a larger square of edge 6.3 cm.

To find:

The area of the remaining tin.

Solution:

Area of a square is:

Area=a^2

Where, a is the edge of the square.

Area of the smaller square is:

A_1=(3.7)^2

A_1=13.69

Area of the larger square is:

A_2=(6.3)^2

A_2=39.69

The area of the remaining tin is:

A=A_2-A_1

A=39.69-13.69

A=26

Therefore, the area of the remaining tin is 26 sq. cm.

8 0
2 years ago
Find the points on the ellipse 4x2 + y2 = 4 that are farthest away from the point (−1, 0).
Hitman42 [59]
<span>The two points that are most distant from (-1,0) are exactly (1/3, 4sqrt(2)/3) and (1/3, -4sqrt(2)/3) approximately (0.3333333, 1.885618) and (0.3333333, -1.885618) Rewriting to express Y as a function of X, we get 4x^2 + y^2 = 4 y^2 = 4 - 4x^2 y = +/- sqrt(4 - 4x^2) So that indicates that the range of values for X is -1 to 1. Also the range of values for Y is from -2 to 2. Additionally, the ellipse is centered upon the origin and is symmetrical to both the X and Y axis. So let's just look at the positive Y values and upon finding the maximum distance, simply reflect that point across the X axis. So y = sqrt(4-4x^2) distance is sqrt((x + 1)^2 + sqrt(4-4x^2)^2) =sqrt(x^2 + 2x + 1 + 4 - 4x^2) =sqrt(-3x^2 + 2x + 5) And to simplify things, the maximum distance will also have the maximum squared distance, so square the equation, giving -3x^2 + 2x + 5 Now the maximum will happen where the first derivative is equal to 0, so calculate the first derivative. d = -3x^2 + 2x + 5 d' = -6x + 2 And set d' to 0 and solve for x, so 0 = -6x + 2 -2 = -6x 1/3 = x So the furthest point will be where X = 1/3. Calculate those points using (1) above. y = +/- sqrt(4 - 4x^2) y = +/- sqrt(4 - 4(1/3)^2) y = +/- sqrt(4 - 4(1/9)) y = +/- sqrt(4 - 4/9) y = +/- sqrt(3 5/9) y = +/- sqrt(32)/sqrt(9) y = +/- 4sqrt(2)/3 y is approximately +/- 1.885618</span>
7 0
3 years ago
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