The geometry of a ______________ makes it a very stable shape.

Which of the following would result in butyl phenyl ether as the major product? a. Reaction of phenoxide with 1-bromobutane b. R

AlladinOne [14]

Answer:

Reaction of 1-butanol with bromobenzene

Explanation:

The reaction would yield ether as the major product is the reaction of the 1-butanol with bromobenzene. This is because the reaction does not have the large percentage of the undesired side product. In fact, the major product is about 85 % in composition, compared to the 15 % of the minor product. Hence, the reaction is efficient.

4 0

4 years ago

Once the torch is lit why must the acetylene flow be increased until the flame stops smoking

mojhsa [17]

Once the torch is lit, the acetylene flow must be increased until the flame stops smoking <span>before the oxygen is turned on for adjustment in order to keep the tip of the torch cool.

You should also note that while lighting the torch, you should keep the spark lighter near the tip but not covering it.</span>

5 0

3 years ago

What does a student need to know about double bonds and triple bonds when predicting molecular geometry of molecules?

zhuklara [117]

This problem is asking for an explanation of what we need to know about double and triple bonds to successfully predict molecular geometries in molecules. At the end, one comes to the conclusion that double and triple bonds contribute to the degree in which an atom is bonded and they also determine the lone pairs, which, at the same time, define the molecular geometry.

<h3>Molecular geometry:</h3>

In chemistry, molecules are not necessarily flat arrangements of atoms, yet they have specific bond angles, orientations and shapes, which define the molecular geometry. In such a way, we can use the VSEPR theory in order to know the molecular geometry of a molecule; however, we first need its Lewis structure or at least the number and type of bonds to do so.

Consider water and carbon dioxide; the former has two hydrogen to oxygen bonds (O-H) and 2 lone pairs because O has six valence electrons but just 2 are bonded to complete the octet, so 4 unpaired electrons lead to two lone pairs. On the other hand, the latter has two double bonds (C=O) and 0 lone pairs because carbon has four valence electrons and they are all bonded to complete the octet.

In such a way, one can see how the double bond affected the bonding in CO2 in contrast to the H2O; situation that also applies to triple bonds, because CO2 has a linear molecular geometry whereas water has a bent one (see attached picture)

Hence, one comes to the conclusion that double and triple bonds contribute to the degree in which an atom is bonded and they also determine the lone pairs, which, at the same time, define the molecular geometry.

Learn more about molecular geometry: brainly.com/question/7558603

Learn more about the VSEPR theory: brainly.com/question/14225705

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2 years ago

How do submarine volcanoes affect autotrophic bacteria?

Anarel [89]

Answer:A large number of autotrophic bacteria—bacteria that produce their own food—live near hydrothermal vents and submarine volcanoes.

These bacteria are considered chemosynthetic, meaning they produce food from chemical reactions usually involving carbon dioxide, oxygen, or hydrogen

5 0

3 years ago

1. A 10 g gold coin is heated from 25°C to 50°C (CAu is 0.13 J/g-°C). What is the H?

Oksanka [162]

The correct answer is + 32.5 J because heat is absorbed here by copper not evolved also after calculation we will find the H value is positive, lets calculate it:
H = m C Δt where:
m = 10 g
C = 0.13 J/g.°C
Δ t = final temperature - initial temperature = 50 - 25 = + 25 °C
so H = 10 x 0.13 x (+25) = + 32.5 J

4 0

3 years ago