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maw [93]
3 years ago
10

Read the question, and then use the drop-down menus to complete the paragraph.

Physics
1 answer:
kondor19780726 [428]3 years ago
4 0

Answer:

The most abundant gas in Earth’s atmosphere is nitrogen, followed by oxygen, which is needed to burn wood and fuel. The third-most abundant gas is argon. The amount of carbon dioxide in the atmosphere is very small, making up just 0.33% of the atmosphere, but it is very important because plants use it to make simple sugars. Another important gas is water vapor, which condenses around small particles in the atmosphere to form clouds and then rain.

Explanation:

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A sphere of radius 0.081029 m is made of aluminum. It is submerged in flowing water with a temperature of 25 °C that results in
Dimas [21]

Answer:

its surface temperature = 54.84 ° C

Explanation:

The density of aluminium (\rho) = 2700 kg/m ³

Heat capacity ( c_p) = 897 J/Kg.K

radius of the sphere (r) = 0.081029 m

T \infty = 25 °C

T_i = 124.978  °C

time (t) = 767.276 s

Using the formula :

\frac{T-T_{ \infty} }{T_i - T_{\infty}}= e^{-\frac{hA}{\rho V c_p}}*t

where.

\frac{V}{A}= \frac{r}{3}

Replacing our values ;we have:

\frac{T-25 }{124.978 - 25}= e^{-\frac{-103.067*3}{2700*897*0.081029}}*767.276

\frac{T-25 }{124.978 - 25}= e^{{-0.001576}*767.276

\frac{T-25 }{124.978 - 25}= e^{-1.209}

\frac{T-25 }{99.978}= 0.2985

{T-25 }= 0.2985*{99.978}

{T-25 }= 29.843433

{T= 29.843433+25 }

{T= 54.843433

T ≅ 54.84 ° C

Therefore, its surface temperature = 54.84 ° C

6 0
4 years ago
I NEED THIS A SOON AS POSSIBLE
vivado [14]

Work is done when spring is extended or compressed. Elastic potential energy is stored in the spring. Provided inelastic deformation has not happened, the work done is equal to the elastic potential energy stored.

6 0
3 years ago
Read 2 more answers
Which of the following graphs best represents the reading on the scale
melisa1 [442]
The first figure matches the description
5 0
3 years ago
Which can occur in a physical change?
adell [148]

Answer:

the mass can arrange

Explanation:

4 0
3 years ago
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High-speed stroboscopic photographs show that the head of a -g golf club is traveling at m/s just before it strikes a -g golf ba
pav-90 [236]

The question is incomplete. The complete question is :

High-speed stroboscopic photographs show that the head of a 200 g golf club is traveling at 60 m/s just before it strikes a  50 g golf ball at rest on a tee. After the collision, the club head travels (in the same direction) at 40 m/s. Find the speed of the golf ball just after impact.

Solution :

We know that momentum = mass x velocity

The momentum of the golf club before impact = 0.200 x 60

                                                                             = 12 kg m/s

The momentum of the ball before impact is zero. So the total momentum before he impact is 12 kg m/s. Therefore, due to the conservation of momentum of the two bodies after the impact is 12 kg m/s.

Now the momentum of the club after the impact is = 0.2 x 40

                                                                                    = 8 kg m/s

Therefore the momentum of the ball is = 12 - 8

                                                                = 4 kg m/s

We know momentum of the ball, p = mass x velocity

                                                     4 = 0.050 x velocity

∴ Velocity =  $\frac{4}{0.050}$

                 = 80 m/s

Hence the speed of the golf ball after the impact is 80 m/s.

6 0
3 years ago
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