Answer:
its surface temperature = 54.84 ° C
Explanation:
The density of aluminium
= 2700 kg/m ³
Heat capacity
= 897 J/Kg.K
radius of the sphere (r) = 0.081029 m
= 25 °C
= 124.978 °C
time (t) = 767.276 s
Using the formula :

where.

Replacing our values ;we have:








T ≅ 54.84 ° C
Therefore, its surface temperature = 54.84 ° C
Work is done when spring is extended or compressed. Elastic potential energy is stored in the spring. Provided inelastic deformation has not happened, the work done is equal to the elastic potential energy stored.
The first figure matches the description
The question is incomplete. The complete question is :
High-speed stroboscopic photographs show that the head of a 200 g golf club is traveling at 60 m/s just before it strikes a 50 g golf ball at rest on a tee. After the collision, the club head travels (in the same direction) at 40 m/s. Find the speed of the golf ball just after impact.
Solution :
We know that momentum = mass x velocity
The momentum of the golf club before impact = 0.200 x 60
= 12 kg m/s
The momentum of the ball before impact is zero. So the total momentum before he impact is 12 kg m/s. Therefore, due to the conservation of momentum of the two bodies after the impact is 12 kg m/s.
Now the momentum of the club after the impact is = 0.2 x 40
= 8 kg m/s
Therefore the momentum of the ball is = 12 - 8
= 4 kg m/s
We know momentum of the ball, p = mass x velocity
4 = 0.050 x velocity
∴ Velocity = 
= 80 m/s
Hence the speed of the golf ball after the impact is 80 m/s.