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3 years ago

2C2H2 + 5O2 → 4CO2 + 2H2O

Chemistry

1 answer:

Mumz [18]3 years ago

8 0

Answer:

d. Two moles of carbon dioxide were produced from this reaction

Explanation:

The given chemical reaction can be written as follows;

2C₂H₂ + 5O₂ → 4CO₂ + 2H₂O

From the above chemical reaction, we have;

Two moles of C₂H₂ reacts with five moles of O₂ to produce four moles of CO₂ and two moles of H₂O

We have;

One mole of C₂H₂ will react with two and half moles of O₂ to produce <em>two moles of CO₂</em> and one mole of H₂O

Therefore, in the above reaction, when one mole of C₂H₂ is used, two moles of CO₂ will be produced.

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3 years ago

Identify three nonmetal atoms that, when bonded covalently, have an argon electron configuration.

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Answer:

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3 years ago

How many moles of NH3 can be produced from 12.0 mol of H2 and excess N2? Express your answer numerically in moles. View Availabl

VladimirAG [237]

Answer:

A) 8.00 mol NH₃

B) 137 g NH₃

C) 2.30 g H₂

D) 1.53 x 10²⁰ molecules NH₃

Explanation:

Let us consider the balanced equation:

N₂(g) + 3 H₂(g) ⇄ 2 NH₃(g)

Part A

3 moles of H₂ form 2 moles of NH₃. So, for 12.0 moles of H₂:

$12.0molH_{2}.\frac{2molNH_{3}}{3molH_{2}} =8.00molNH_{3}$

Part B:

1 mole of N₂ forms 2 moles of NH₃. And each mole of NH₃ has a mass of 17.0 g (molar mass). So, for 4.04 moles of N₂:

$4.04molN_{2}.\frac{2molNH_{3}}{1molN_{2}} .\frac{17.0gNH_{3}}{1molNH_{3}} =137gNH_{3}$

Part C:

According to the <em>balanced equation</em> 6.00 g of H₂ form 34.0 g of NH₃. So, for 13.02g of NH₃:

$13.02gNH_{3}.\frac{6.00gH_{2}}{34.0gNH_{3}} =2.30gH_{2}$

Part D:

6.00 g of H₂ form 2 moles of NH₃. An each mole of NH₃ has 6.02 x 10²³ molecules of NH₃ (Avogadro number). So, for 7.62×10⁻⁴ g of H₂:

$7.62 \times 10^{-4} gH_{2}.\frac{2molNH_{3}}{6.00gH_{2}} .\frac{6.02\times 10^{23}moleculesNH_{3} }{1molNH_{3}}=1.53\times10^{20}moleculesNH_{3}$

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4 years ago

A small piece of Cr metal reacts with dilute HNO3 to form H2 (g), which is collected over water at 18 C in a large flask. The to

Sauron [17]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The partial pressure is $P_p= 737.5 mm \ of \ Hg$

Explanation:

The Partial pressure of $H_2$ is mathematically represented as

$P_p = P_T -P_w$

Where $P_T$ is the total pressure of water with a value of 15.5 mm of Hg

$P_w$ is the partial pressure of water with a value 753 mm of Hg

Now substituting values

$P_p = 753-15.5$

$P_p= 737.5 mm \ of \ Hg$

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