Explanation:
Work done is a physical quantity that is defined as the force applied to move a body through a particular distance.
Work is only done when the force applied moves a body through a distance.
Work done = Force x distance
The maximum work is done when the force is parallel to the distance direction.
The minimum work is done when the force is at an angle of 90° to the distance direction.
So to solve this problem;
multiply the force applied by Zack and distance through which the bull was pulled.
Answer:
The time is 0.5 sec.
Explanation:
Given that,
Voltage V= 12.00 V
Inductance L= 1.20 H
Current = 3.00 A
Increases rate = 8.00 A
We need to calculate change in current

We need to calculate the time interval
Using formula of inductor


Where,
= change in current
V = voltage
L = inductance
Put the value into the formula


Hence, The time is 0.5 sec.
Answer:
the last one, the third one, and the first one.
Answer:
You pull on the oars. By the third law, the oars push back on your hands, but that’s irrelevant to the motion of the boat. The other end of each oar (the blade) pushes against the water. By the third law, the water pushes back on the oars, pushing the boat forward.