If mass increases - Force of gravity increases A. True B.False

Is the following chemical equation balanced? MgI2 + Br2 MgBr2 + I2 yes no

Brums [2.3K]

Yes

Explanation:

This chemical equation:

$Mg I_2 + Br_2 \rightarrow Mg Br_2 + I_2$

is balanced, because the number of atoms of each element is the same on the reactant side and on the product side. In fact:

- Mg: one atom on the left, one on the right

- I: 2 atoms on the left, and 2 on the right

- Br: 2 atoms on the left, and 2 on the right

So, the reaction is balanced.

3 0

3 years ago

Read 2 more answers

4. A vehicle

Gnom [1K]

Answer:

Average acceleration, $a=2.77\ m/s^2$

Explanation:

Given that,

Initial velocity, u = 0 km/h

Final velocity, v = 100 km/h = 27.77 m/s

Time, t = 10 s

We need to find the average acceleration of the vehicle. It is given by the change in velocity divided by time. Som,

$a=\dfrac{v-u}{t}\\\\a=\dfrac{27.77-0}{10}\\\\a=2.77\ m/s^2$

So, its average acceleration is $2.77\ m/s^2$ .

5 0

4 years ago

According to the pressure-flow hypothesis, why must sieve-tube elements in phloem be living cells?

Zigmanuir [339]

Base from the pressure-flow hypothesis, the sieve tube in the phloem should be living cells because sugars are transported across the membranes by the active transport which needs ATP that is produced during respiration. Hope this helps.

3 0

4 years ago

You have a grindstone (a disk) that is 95.2 kg, has a 0.399 m radius, and is turning at 93 rpm, and you press a steel axe agains

olya-2409 [2.1K]

Answer:

angular acceleration is -0.2063 rad/s²

Explanation:

Given data

mass m = 95.2 kg

radius r = 0.399 m

turning ω = 93 rpm

radial force N = 19.6 N

kinetic coefficient of friction μ = 0.2

to find out

angular acceleration

solution

we know frictional force that is = radial force × kinetic coefficient of friction

frictional force = 19.6 × 0.2

frictional force = 3.92 N

and

we know moment of inertia that is

γ = I ×α = frictional force × r

so

γ = 1/2 mr²α

α = -2f /mr

α = -2(3.92) /95.2 (0.399)

α = - 7.84 / 37.9848 = -0.2063

so angular acceleration is -0.2063 rad/s²

3 0

3 years ago

If a car takes a banked curve at less than the ideal speed, friction is needed to keep it from sliding toward the inside of the

exis [7]

Answer:

ideal speed(v)≅17m/s

Explanation:

Given: Radius, r = 110 m

Angle(α) = 15°

g=9.81m/ $s^{2}$

Find; (a) The ideal speed, v.

tanα= $\frac{v^{2} }{rg}$

make V subject of the formula;

v= $\sqrt{rgtan\alpha }$

v= $\sqrt{110 * 9.81* tan15}$

v= $\sqrt{289.144}$

v≅17m/s

3 0

3 years ago