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yanalaym [24]
2 years ago
15

A rug sits in a sunny place on the floor for a long time. Kiara thinks that light from the sun can cause the rug’s color to fade

over time. Can light from the sun cause the rug’s color to fade?
Physics
1 answer:
laiz [17]2 years ago
6 0

Answer:

Yes, the sun can fade the color of the rug.

Explanation:

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Three mountain climbers set out to climb a mountain from the same altitude and all arrive at the same location at the top. Mount
vampirchik [111]
C did the most effort, but A walked the longest, so a reasonable answer is that they all did the same amount of work, as B simply mediates.
6 0
3 years ago
Read 2 more answers
An automobile with a mass of 1240.00 kg has 3.99 m between
Vitek1552 [10]

Answer:

948.15248\ N

5134.04751\ N

Explanation:

F_f = Force on front wheels

F_r = Force on rear wheels

Distance between CG and rear wheel = 3.99-0.622 = 3.368 m

F_r=1240\times 9.81-F_f

As the forces are conserved we have

(1240\times 9.81-F_f)3.368=F_f\times 0.622\\\Rightarrow 12164.4-F_f=\dfrac{0.622F_f}{3.368}\\\Rightarrow 12164.4-F_f=0.18467F_f\\\Rightarrow F_f=\dfrac{12164.4}{1.18467}\\\Rightarrow F_f=10268.09503\ N

On rear wheels

F_r=1240\times 9.81-10268.09503\\\Rightarrow F_r=1896.30497\ N

The force on each rear whees is \dfrac{1896.30497}{2}=948.15248\ N

Force on each front wheel is \dfrac{10268.09503}{2}=5134.04751\ N

8 0
3 years ago
A flat surface of area 3.20 m2 is rotated in a uniform electric field of magnitude e = 6.20 x 105 n/c. determine the electric fl
krok68 [10]
The electric flux on a surface of area A in a uniform electric field E is given by 
φ = EA cos θ
where θ = the angle between the directions of E and a normal vector to the surface of the area.
See the diagram shown below.

When the electric field is perpendicular to the surface, then θ = 0°, and
φ = EA cos(0°)  = (6.20 x 10⁵ N/C)*(3.2 m²) = 1.984 x 10⁶ (N-m²)/C

When the electric field is parallel to the area, then θ = 90°, and
φ = EA cos(90°) = 0

Answer:
(a) 1.984 x 10⁶ (N-m²)/C
(b) 0

3 0
3 years ago
Suppose you have a string of length LaTeX: LL clamped down on both sides. Is it possible for the wavelength of a standing wave o
mamaluj [8]

Answer:

Explanation:

For a string of length L clamped down on both ends , for fundamental mode of vibration

2 . λ / 4 = L

= λ / 2 = L

λ = 2 L

For other modes , the formula is

n . λ/2 = L where n is an integer .

λ = 2L / n

if n = 6

λ = 2L / 6

= L/3

So wavelength = L/3 is possible .

7 0
3 years ago
This problem has been solved! See the answer A 21.5 kg person climbs up a uniform 85 N ladder. The upper end of the ladder rests
xenn [34]

Answer:

 μ = 0.179

Explanation:

For this exercise we use the rotational equilibrium condition, where we set a reference system at the top of the ladder where it is in contact with the parent, we will assume the counterclockwise rotations as positive

         ∑ τ = 0

         W_stairs x/2 + W_man x’+ fr y - N x = 0

          fr y = -W_stairs x/2 - W_man x’ + N x

let's use trigonometry for distances

* the man up the ladder 78%

            l ’= 0.78 L

            cos 59 = x ’/ l’

            x’= 0.78 L cos 59

* the horizontal distance

           cos 59 = x / L

            x = L cos 59

* vertical distance

            sin 59 = Y / L

            y = L sin 59

we substitute

           fr L sin 59 = -W_stairs Lcos59 / 2 - W_man 0.78 L cos59 + N L cos59

           fr sin 59 = - ½ W_stairs cos 59 - 0.78 W_man cos 59 + N cos 59

           fr = ctan 59  (N - ½ W_stairs - 0.78 W_man)     (1)

Let's write the translational equilibrium equations

Y axis  

           N -W_stairs - W_man = 0

           N = W_stairs + W_man

           N = 85 + 21.5 9.8

           N = 295.7 N

we substitute in 1

           fr = ctg 59 (295.7 - ½ 85 - 0.78 21.5 9.8)

           fr = 0.6 (295.7 - 42.5 - 164.346)

           fr = 52.89 N

the expression for the friction force is

            fr = μ N

            μ = fr / N

             μ = 52.89 / 295.7  

             μ = 0.179

8 0
3 years ago
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