Answer:
439.7nm
Explanation:
Energy of a quantum can be calculated using below formula
E=hv...........eqn(1)
But v=λ/ c .........eqn(2)
If we substitute eqn(2) into eqn(1) we have
E= hc/(λ)
Where E= energy
h= Plank's constant= 6.62607004 × 10-34 m2 kg / s
c= speed of light
c= 2.998 × 10^8 m/s
λ= wavelength= ?
But the energy was given in Kj , it must be converted to Kj/ photon for unit consistency.
Energy E= 272 kJ/mol × 1mol/6.02× 10^23
Energy= 451.83× 10^-24 Kj/ photon
E= hc/(λ)...........eqn(1)
If we make λ subject of the formula
λ= hc/E
Then substitute the values we have
λ= [(6.626 × 10^-34) × (2.998 × 10^8)]/451.83× 10^-24
λ=(0.00043965) × (1Kj/1000J) × (10^9nm/1m)
λ=439.7nm
Hence, the longest wavelength of radiation with enough energy to break carbon-sulfur bonds is 439.7nm
There doesn't seem to be a question. I'm going to take a wild guess and say that what you want is a balanced equation.
Here is the unbalanced equation
NH4NO3(s) ===> N2(g) + O2(g) + H2O(g) Start by balancing the N2 on the left
2NH4NO3(s) ===> N2(g) + O2(g) + H2O(g) Now balance the hydrogen
2NH4NO3(s) ===> N2(g) + O2(g) + 4H2O(g) You need 8 Hs
Go for the Oxygens.
They are balanced. There's 6 on the left and 4+2 on the right.
This is b nuclear energy
Because it turns into gas
MilliLiters is what you use to measure the density of liquids