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prohojiy [21]
2 years ago
6

Looking at the periodic table, which of these elements has the smallest atomic radius?

Chemistry
1 answer:
Sauron [17]2 years ago
8 0
Helium
Remember: electron filling of atomic shell  ...
 The element which have electron in the lowest quantum shell will have the smallest atomic radius\

He:1s1   (Helium)

H:1s2   (hydrogen)
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For the reaction 3h2(g) + n2(g) 2nh3(g), kc = 9.0 at 350°c. calculate g° at 350°c.
miss Akunina [59]
When ΔG° is the change in Gibbs free energy

So according to ΔG° formula:

ΔG° =  - R*T*(㏑K)

here when K = [NH3]^2/[N2][H2]^3 = Kc 

and Kc = 9 

and when T is the temperature in Kelvin = 350 + 273 = 623 K

and R is the universal gas constant = 8.314 1/mol.K

So by substitution in ΔG° formula:

∴ ΔG° = - 8.314 1/ mol.K * 623 K *㏑(9)

           = - 4536 
4 0
3 years ago
Who made the first periodic table
ale4655 [162]
The other dude is rude wrong

The correct answer is Dmitri Mendeleev
8 0
2 years ago
Describe the properties of alkali metals. based on their electronic arrangement, explain whether they exist alone in nature.
saul85 [17]

The alkali metals can't exist alone in nature because of incomplete outermost shell of alkali metals.

<h3>What are the  properties of alkali metals?</h3>

The alkali metals have the high thermal and electrical conductivity. It has high lustre, ductility, and malleability as compared to other materials. Each alkali metal atom has one electron in its outermost shell which make more reactive.

So we can conclude that the alkali metals can't exist alone in nature because of incomplete outermost shell of alkali metals.

Learn more about metal here: brainly.com/question/25597694

#SPJ1

5 0
2 years ago
Balance the following chemical equation <br> __Mg+__O2–&gt;__MgO
mario62 [17]

Answer:

2Mg^+ +O2 right arrow 2MgO

Explanation:

6 0
3 years ago
Read 2 more answers
Calculate the heat required to convert 5.0 g of ice at 0.0 c to steam at 100
Fiesta28 [93]
Heat= latent heat of fusion+sensible heat+ latent heat of vapourization
=(79.7*5)+(5*100*1)+(540*5)
=3598.5 cal
6 0
3 years ago
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