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JulijaS [17]
3 years ago
10

Which statement describes an example of destructive interference?

Physics
1 answer:
a_sh-v [17]3 years ago
4 0

Answer:

B. Light shining on a surface has gaps after passing through two

slits.

Explanation:

Destructive interference is said to occur when two waves cancel out each other. The occurrence of this phenomenon implies that the waves have equal amplitude in opposite directions.

When light shinning on a surface has two gaps after passing through two slits, then the waves have interfered destructively which led to the gaps.

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Explanation:

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Diego hypothesizes that the Earth wobbles on its axis in a pattern that is repeated every 20,000 years.
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I’m not sure but I think it’s D because we don’t have 20,000 years to make observations
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Read 2 more answers
A solenoidal coil with 25 turns of wire is wound tightly aroundanother coil with 300 turns. The inner solenoid is 25.0 cm long a
Aneli [31]

Answer:

(a). The average magnetic flux through each turn of the inner solenoid is 5.68\times10^{-8}\ Wb

(b). The mutual inductance of the two solenoids is 1.183\times10^{-5}\ H

(c). The emf induced in the outer solenoid by the changing current in the inner solenoid is -0.0207 V.

Explanation:

Given that,

Number of turns of coil = 25

Number of turns of another coil = 300

Length = 25.0 cm

Diameter = 2.00 cm

Current = 0.120 A

Rate \dfrac{di_{2}}{dt}=1.75\times10^{3}\ A/s

(a). We need to calculate the magnetic field due to inner solenoid

Using formula of magnetic field

B=\mu_{0}(\dfrac{N_{2}}{l})I

Put the value into the formula

B=4\pi\times10^{-7}\times(\dfrac{300}{0.25})\times0.120

B=1.81\times10^{-4}\ T

We need to calculate the average magnetic flux through each turn of the inner solenoid

Using formula of magnetic flux

\phi=B\cdot A

Put the value into the formula

\phi=1.81\times10^{-4}\times\pi\times (1.00\times10^{-2})^2

\phi=5.68\times10^{-8}\ Wb

The average magnetic flux through each turn of the inner solenoid is 5.68\times10^{-8}\ Wb

(b). We need to calculate the mutual inductance of the two solenoids

Using formula of mutual inductance

M=\dfrac{N_{1}\phi}{i_{1}}

Put the value into the formula

M=\dfrac{25\times5.68\times10^{-8}}{0.120}

M=0.00001183\ H

M=1.183\times10^{-5}\ H

The mutual inductance of the two solenoids is 1.183\times10^{-5}\ H

(c).  We need to calculate the emf induced in the outer solenoid by the changing current in the inner solenoid

Using formula of emf

\epsilon=-M\dfrac{di_{2}}{dt}

Put the value into the formula

\epsilon=-1.183\times10^{-5}\times1.75\times10^{3}

\epsilon=-0.0207\ V

The emf induced in the outer solenoid by the changing current in the inner solenoid is -0.0207 V.

Hence, (a). The average magnetic flux through each turn of the inner solenoid is 5.68\times10^{-8}\ Wb

(b). The mutual inductance of the two solenoids is 1.183\times10^{-5}\ H

(c). The emf induced in the outer solenoid by the changing current in the inner solenoid is -0.0207 V.

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professor190 [17]
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6 0
3 years ago
A stone is projected at an angle of 50.00 degrees to the horizontal. If
NARA [144]

Answer:

answer is A. 32.14

Explanation:

The initial velocity must be broken up into x and y components.

v_x=v\cdot cos(\theta)

we are given that v=50m/s and \theta=50^\circ

therefore

v_x=50\cdot cos(50^\circ)

v_x=32.14m/s

answer is A. 32.14

6 0
3 years ago
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