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3 years ago

Does the plane of the ecliptic coincide with the plane of the equator? explain.

1 answer:

3 0

<span>no it doesn't. one way to think of it is that the tropic of capricorn is the furthest south the sun's path goes, and the tropic of cancer is the northern most line that the sun traces out. since neither the tropic of capriforn nor the tropic of cancer are on the equator, the sun must be tracing out a different line and hence be on a different plane. also, if the sun was on the same plane as the equator, then we wouldn't have seasons.</span>

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Patients with brain tumors may elect to have a procedure known as Gamma Knife. In a typical Gamma Knife procedure gamma rays are

Allushta [10]

Thinking not sure but gammer rays are high energy and may cause damage to healthy cells

6 0

3 years ago

Read 2 more answers

An object with charge q=−6.00×10−9C is placed in a region of uniform electric field and is released from rest at point A. After

shtirl [24]

Answer:

its a

Explanation:

used google

8 0

3 years ago

Una barra de plata de 335.2 g con una temperatura de 100 ºC se introduce un calorímetro de aluminio de 60 g de masa que contiene

sdas [7]

Respuesta:

0,0560 cal / gºC.

Explicación:

Cantidad de calor; (Q)

Q = mcΔt; Δt = t2 - t1

m = masa, c = capacidad calorífica específica; Δt = cambio de temperatura

c de agua = 1 cal / gºC

c de aluminio = 0,22 cal / gºC

QTotal = Q de agua + Q de aluminio

Q de agua = 450 * 1 * (26 - 23) = 1350 cal

Q de aluminio = 60 * 0.22 * (26 - 23) = 39.6 cal

QTotal = 1350 + 39,6 = 1389,6 cal

Calor perdido = calor ganado

QTotal = calor perdido

- 1389,6 = 335,2 * c * (26 - 100)

-1389,6 = −24804,8 * c

c = 1389,6 / 24804,8

c = 0,056021 cal / gºC.

Capacidad calorífica específica de la plata = 0,0560 cal / gºC.

8 0

3 years ago

You are designing a generator with a maximum emf 8.0 V. If the generator coil has 200 turns and a cross-sectional area of 0.030

shutvik [7]

Answer:

7.1 Hz

Explanation:

In a generator, the maximum induced emf is given by

$\epsilon= 2\pi NAB f$

where

N is the number of turns in the coil

A is the area of the coil

B is the magnetic field strength

f is the frequency

In this problem, we have

N = 200

$A=0.030 m^2$

$\epsilon=8.0 V$

B = 0.030 T

So we can re-arrange the equation to find the frequency of the generator:

$f=\frac{\epsilon}{2\pi NAB}=\frac{8.0 V}{2\pi (200)(0.030 m^2)(0.030 T)}=7.1 Hz$

4 0

3 years ago

Read 2 more answers

Determine the minimum wavelength of light absorbed by (a) diamond, (b) gallium phosphide and (c) tin sulfide if the gap energies

Talja [164]

I would say B.
I hope this helps!

7 0

3 years ago